# please some one can derrive   this   theorem  for   alpha   equal to beta  i had shown in the image attached

runo
30 Points
7 years ago
We know that the angle subtended  by an arc at the center is double  the angle subtended by the arc at any point in the remaining part of the circle.So in figure,we have
2
therefore,
alpha=beta
runo
30 Points
7 years ago
$< POQ=2< PRQ and < POQ=2< PSQ, 2< PRQ= 2< PSQ, therefore, < PRQ= < PSQ.So, alpha=beta.$
Vaibhav Gupta
73 Points
7 years ago
@runo