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PLEASE GIVE ME A DETAILED SOLUTION TO THE ABOVE QUESTION WITH ALL THE STEPS .

VIBHU SHARAN DIXIT , 6 Years ago
Grade 10
anser 1 Answers
Arun

Last Activity: 6 Years ago

Dear student
 
let the point of contact of tangents are M and N
 
then OPMN forms a cyclic quadrilateral hence angle MON = 120 degrees
 
now also angle MPO = 30 degrees and angle MOP = 60 degrees
 
as MO = a
 
hence in right angled triangle OPM,
 
sin 30 = a/ OP
 
OP = 2a

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