In a triangle ABC, a, b, c are the lengths of its sides and A,B,C are the angles of triangle ABC. The correct relation is given by.
(A) (b−c)(B−C2)=a cosA2

(B) (b−c)cosA2=a sin(B−C2)

(C) (b−c)sin (B−C2)=a cosA2

(D) (b−c)sin A2=2 a sin(B+C2)

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Pawan Prajapati · Answer

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In a triangle ABC, a, b, c are the lengths of its sides and A,B,C are the angles of triangle ABC. The correct relation is given by. (A) (b−c)(B−C2)=a cosA2 (B) (b−c)cosA2=a sin(B−C2) (C) (b−c)sin (B−C2)=a cosA2 (D) (b−c)sin A2=2 a sin(B+C2)

In a triangle ABC, a, b, c are the lengths of its sides and A,B,C are the angles of triangle ABC. The correct relation is given by.
(A) (b−c)(B−C2)=a cosA2

(B) (b−c)cosA2=a sin(B−C2)

(C) (b−c)sin (B−C2)=a cosA2

(D) (b−c)sin A2=2 a sin(B+C2)

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In a triangle ABC, a, b, c are the lengths of its sides and A,B,C are the angles of triangle ABC. The correct relation is given by. (A) (b−c)(B−C2)=a cosA2 (B) (b−c)cosA2=a sin(B−C2) (C) (b−c)sin (B−C2)=a cosA2 (D) (b−c)sin A2=2 a sin(B+C2)

In a triangle ABC, a, b, c are the lengths of its sides and A,B,C are the angles of triangle ABC. The correct relation is given by. (A) (b−c)(B−C2)=a cosA2 (B) (b−c)cosA2=a sin(B−C2) (C) (b−c)sin (B−C2)=a cosA2 (D) (b−c)sin A2=2 a sin(B+C2)

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In a triangle ABC, a, b, c are the lengths of its sides and A,B,C are the angles of triangle ABC. The correct relation is given by.
(A) (b−c)(B−C2)=a cosA2

(B) (b−c)cosA2=a sin(B−C2)

(C) (b−c)sin (B−C2)=a cosA2

(D) (b−c)sin A2=2 a sin(B+C2)