If the roots of the equation (a-b) x 2 + (b-c) x + (c-a) = 0 are equal , then prove that 2a = b + c .

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Arun · Answer

Dear student As we see that x = 1 satisfy this Hence both roots are 1. Hence Product of roots = 1 = c-a /a-b a-b = c -a 2a = b +c

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If the roots of the equation (a-b) x 2 + (b-c) x + (c-a) = 0 are equal , then prove that 2a = b + c .

If the roots of the equation (a-b) x² + (b-c) x + (c-a) = 0 are
equal , then prove that 2a = b + c .

1 Answers

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If the roots of the equation (a-b) x 2 + (b-c) x + (c-a) = 0 are equal , then prove that 2a = b + c .

If the roots of the equation (a-b) x2 + (b-c) x + (c-a) = 0 are equal , then prove that 2a = b + c .

1 Answers

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If the roots of the equation (a-b) x² + (b-c) x + (c-a) = 0 are
equal , then prove that 2a = b + c .