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If sin theta/x = cos theta /y then sin theta - cos theta is?
sin theta/x = cos theta/ysin theta/cos theta = x/ytan theta = x/y sin theta = x/root(x2+y2) and cos theta = y/root(x2+y2)sin theta – cos theta = (x-y)/root(x2+y2)
sin theta/x=costheta/ysin theta/cos theta = x/ytherefore, sin theta=x and cos theta = y then sin theta-cos theta = x-y/root 1root 1 because its value is 1 so we asssumeroot 1 can be written in trigonometric form that is sin^2a+cos^a=1 so sin theta – cos theta = x-y/root sin^2 theta + cos^2 theta = x-y/root x^2+y^2since the valuse of sin and cos in this question above.
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