Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

If hcf of 81 and 237 can be expressed as 81x + 237y then find the value of 3x+2y

If hcf of 81 and 237 can be expressed as 81x + 237y then find the value of 3x+2y

Grade:10

1 Answers

Arun
25763 Points
3 years ago

By Euclid's Division Algorithm,

237=81(2)+(75)

81=75(1) + (6)

75=6(12)+(3)

6=3(2)+(0)

Hcf =3

Expressing it in the form of 237x+81y=HCF

3=75-6(12)  { From 2nd last step}

3=75-(81-75)(12)  {Substituting}

3=75-(81*12-75*12)

3=75-81*12+75*12

3=75(13)-81(12)

3=(237-81*2)(13)-81(12)

3=237(13)-81(38)

3=237(13)+81(-38)  {we need an expression in the form 237x + 81y }

Therefore, x =13 , y =- 38

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free