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`        if (a-b)/c +(b-c)/a +(c+a)/b=1 then prove 1/a= 1/b + 1/c`
one year ago

```							The question is not appropriate my dear friend. You are somewhere mistaken. It cannot be proved by any method. Thank youHope u reconsider it
```
one year ago
```							i have solved it(a-b)/c +(b-c)/a +(c+a)/b=1(a-b)/c +(b-c)/a +(c+a)/b=1+1-1(a-b)/c+1 +(b-c)/a-1 +(c+a)/b-1=0{(a-b)/c+1} +{(b-c)/a-1} +{(c+a)/b-1}=0(a-b+c)/c +(b-c-a)/a +(c+a-b)/b=0(a-b+c)/c -(-b+c+a)/a +(c+a-b)/b=0(a-b+c)/c -(a-b+c)/a +(a-b+c)/b=0(a-b+c)(1/c-1/a+1/b)=0so {1/c-1/a+1/b}=0=>1/a=1/b+1/c(thanks for trying , i solved it few days ago )
```
one year ago
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