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An urn contains 6 balls of which two are red and four are black. Two balls are drawn at random. The probability that they are of different colours is (i)⅖ (ii)1/15 (iii)8/15 (iv)4/15

An urn contains 6 balls of which two are red and four are black. Two balls

are drawn at random. The probability that they are of different colours is

(i)⅖ (ii)1/15 (iii)8/15 (iv)4/15

Grade:12

1 Answers

Harshit Singh
askIITians Faculty 5965 Points
one year ago
Dear Student

Given that, the total number of balls = 6 balls

Let A and B be the red and black balls respectively,

The probability that two balls drawn are different = P(the first ball drawn is red)(the second ball drawn is black)+ P(the first ball drawn is black)P(the second ball drawn is red)

= (2/6)(4/5) + (4/6)(2/5)

=(8/30)+ (8/30)

= 16/30

= 8/15
hence, C is the correct option

Thanks

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