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An urn contains 6 balls of which two are red and four are black. Two balls are drawn at random. The probability that they are of different colours is (i)⅖ (ii)1/15 (iii)8/15 (iv)4/15
Dear StudentGiven that, the total number of balls = 6 ballsLet A and B be the red and black balls respectively,The probability that two balls drawn are different = P(the first ball drawn is red)(the second ball drawn is black)+ P(the first ball drawn is black)P(the second ball drawn is red)= (2/6)(4/5) + (4/6)(2/5)=(8/30)+ (8/30)= 16/30= 8/15hence, C is the correct optionThanks
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