a)If A and B are acute angles such that tanA=1/2, tanB=1/3 and tan(A+B)=tanA+taB/1-tanAtanB, show that A+B=45 o . b)sinB = cos(B-45), where B and (B-45) are acute angles.Find the value of the angle B?

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Arun · Answer

I Given that, tanA = 1/3 tanB = 1/2 tan (A+ B) = ( tanA + tanB) / (1 - tanA tanB) = (1/3 +1/2) / (1- 1/3×1/2) = (5/6) / ( 1- 1/6) = (5/6)/(5/6) tan (A+B) =1 Hence (A + B) = 45°

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a)If A and B are acute angles such that tanA=1/2, tanB=1/3 and tan(A+B)=tanA+taB/1-tanAtanB, show that A+B=45 o . b)sinB = cos(B-45), where B and (B-45) are acute angles.Find the value of the angle B?

a)If A and B are acute angles such that tanA=1/2, tanB=1/3 and tan(A+B)=tanA+taB/1-tanAtanB,
show that A+B=45^o.
b)sinB = cos(B-45), where B and (B-45) are acute angles.Find the value of the angle B?

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a)If A and B are acute angles such that tanA=1/2, tanB=1/3 and tan(A+B)=tanA+taB/1-tanAtanB, show that A+B=45 o . b)sinB = cos(B-45), where B and (B-45) are acute angles.Find the value of the angle B?

a)If A and B are acute angles such that tanA=1/2, tanB=1/3 and tan(A+B)=tanA+taB/1-tanAtanB,show that A+B=45o.b)sinB = cos(B-45), where B and (B-45) are acute angles.Find the value of the angle B?

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a)If A and B are acute angles such that tanA=1/2, tanB=1/3 and tan(A+B)=tanA+taB/1-tanAtanB,
show that A+B=45^o.
b)sinB = cos(B-45), where B and (B-45) are acute angles.Find the value of the angle B?