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OTP to be sent to Change
ΔG = ΔGo + RT InQ
Where Q is the reaction quotient
When equilibrium is attained, there is no further free energy change i.e. ΔG = 0 and Q becomes equal to equilibrium constant. Hence the above equation becomes.
ΔGo = –RT In K(eq)
or ΔGo = –2.303 RT log K(eq)
In case of galvanic cells. Gibbs energy change ΔG is related to the electrical work done by the cell.
ΔG = -nFE(cell) where n = no. of moles of electrons involved
F = the Faraday constant
E = emf of the cell
If reactants and products are in their standard states ΔGo = –nFEocell
Solved example: Calculate ΔG0 for conversion of oxygen to ozone 3/2 O2 (g) ——> O3 (g) at 298 K, if Kp for this conversion is 2.47 ´ 10-29.
Solution: ΔGo = –2.303 RT log Kp
Where R = 8.314 J/K mol, Kp = 2.47 ´ 10-29, T = 298K
ΔG0 = 16300 J/mol = 163 KJ/mol.
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