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according to me value of x=2 is the solution of equation as x=2 is the root of both quadratic equations we get an inequality that is always true approve if useful
of course it is wrong if x,y,z arein hp then 1/x,1/y,1/z are in ap so on expanding the factorial we coclude that only possible value is n=0 approve if useful
1!+2!+3!+4!=33
Absolutely wrong answer the correct ans is 1728
hii The question is incomplete.complete the question and repost it again
check out this link on flipkart solution of hall and knight is at Rs 429 with free shipping oh sorry but amazon is offering at lower price than flipkart as my price comparer is displaying Rs 399 at...
is this question complete mrudul i think there is some missing in the question , kindly post it again , i will give u answer as best as possible
No, ans is 96 but my ans is also coming 72....
it is sure that 2 is one root of this equation as 4a+2b+c=0 also sum of roots is negative so other root will be negative bcoz if we want multiplication of two numbers negative then one must be...
I think domain is set of R (Real Numbers)
Hello student, Your question is not clear and seems to be incomplete. Please recheck your question and post it again.
according to me there are no common roots of the equations that u have mentioned bcoz frm first eq we conclude that x=1,-1 but any value of x among these two does not satisfy the other equation also...
3879