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Range of f(x) = 4|x|^3 – 3x i dont there is any mod or not since it isnot clearly visible bu i am soolving for mod here, when x > 0 y = 4x^3 – 3x when x y = -4x^3 – 3x Plot both the grapdhs for given ...
Dear Aditya Dev, Srry but your question is incomplete here. Plz Re-post it. Thanks! The eqn. whose sum is to be found is missing.
Solving numerator, (2|x| – 3) 2 - |x| – 6 = > 4|x|^2 + 9 – 12|x| – |x| – 6 => 4|x|^2 -13|x| + 3 = 0 = > 4|x|^2 -12|x| – |x| + 3 = 0 = > 4|x|(|x| – 3) – (|x| – 3) = 0 => (4|x| – 1) (|x| – 3) = 0 |x| = ...
a+3d/a+9d =a+d/a+5d do cross multiyply, (a+3d)(a+5d) = (a+d)(a+9d) a^2 + 5ad + 3ad + 15d^2 = a^2 + 9ad + ad + 9d^2 -2ad + d^2 = 0 or d^2 – 2ad = 0 d(d – 2a) = 0 d cannot be zero. Therefore, d = 2a k...
Put x 2 +2 =y the equation reduces to y 2 -6xy+8x 2 =0 (y-4x)(y-2x)=0 This will give two quadratic equations in x which can now be easily solved x 2 -4x+2= 0 and x 2 -2x+2
@ manish Kindly mention the topic in which u are facing problem , beacuse , relation and function chapter contains very much concept , which needs to be covered as far as jee is concerned . ,, u can...
Totally there are 200
\quad \quad { x }^{ 3 }+ax\quad =\quad -b\\ { x }^{ 3 }+ax+b\quad =\quad 0\quad \quad will\quad have\quad all\quad real\quad roots\quad if\quad \\ curve\quad y=\quad f(x)\quad =\quad { x }^{ 3...
Hii the question is not clear .Kindly reost it again and we will get back at you
Convert both of them to 3log 2 ( log 2 x * log 4 x )
With the further assumption that f(x) is continuous, we can prove that f(x) = x is the only function satisfying the given conditions. (otherwise it becomes difficult to deal with transcendental...
@ aditya i am giving the apporoach to solve this question here we nned to take quadratic equation in b means a as constant. so that quadratic equation should take ionly positive values. means its...
The given equation can also be written as …..........................................................................
0 to 2pi ,,,,pi/2 to -pi/2 these are the answers to the first two questions... similarly solve the third question and obtain the domain. always remember that denominator not equal to zero and square...
The rlationship between a b c is not clear , please post the question clearly...........................
Every element of X has three choices – (i) belong to Y (ii) belong to Z (iii) belong to neither So, the total number of ways = 3 5 = 243. (including the possibility that both Y and Z are null sets as ...
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