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Can you please answer this question..The nu ver of ordered pairs (m,n) where m,n€{1,2,...........,50} such that 6^n + 9^m is a multiple of 5
P(min 3 union max 7)= p(min 3)+ p(max 7) - p( min3 intersection max7). Now put the values........... 8C3 by 10C3. +7C3 by 10C3 -5C3 by 10C3 .... Solve this u get answer correctlt
For particular house probability is 1/3., probability that all 3 apply for same house is 1 by (1/3 ×1/3 ×1/3 )×3
Probability of choosing any month out of 12 month =1/12 Probability that the 13th day is Friday if the 1st day say starts with Sunday =1/7 Thus required probability =1/12×1/7 =1/84
as a,b,c are in A.P. so 2b=a+c..................(i) If (b+c) , (a+c) , (a+b) will be in A.P. ,,then (b+c) + (a+b)=2(a+c). Now (b+c) + (a+b)= b+c+a+b =2b+a+c =2b+2b {from(i)} =4b =2.2b =2(a+c) {from...
(3z-1)^4= -(Z-2)^4 3z-1=2-Z 4z=3 Z=3/4 NOW U CAN SOLVE THIS PLEASE CHECK OUT COURSES WE PROVIDE I HOPE YOU WILL FOUND THISANSWER HELPFUL THANKS FOR POSTING YOUR QUERIES ON ASKIITIANS.COM
Magnitude cannot be negative. Hence to pulsate the negative effect we change the argument by adding the pie to it. And therfore the new point in polar form becomes as => (r,thetha + pi) Learn it.
Magnitude = root(3 + 1) = 2 and the argument that is thetha = arctan(1/root3) = 30 degree + 180 degree = 210 degree = 7pie/3 Hence the polar coordinates would be: => (2,7π/6)
Roots of x 2 +x+1 are imaginary that are w and w^2 which are the cubic roots. Hence this would satify the h(w) eqn. Therfore, h(w) = 0 => wf(1) + wg(1) = 0 or w(f(1) + g(1)) = 0 w cannot be zero hence...
Your question is incomplete. Since it requires the relation for the variable m to n or something that would satisfies it. Kindly Re-Post the question with proper explanation and details . Thanx!
Dear Varun, The questions would be from the pack of 52 cards would belike: Probaibility of kings to be drwan or Probability of Queens from the 52 pack of cards would be? etc. Therefore to solve the...
After plotting all the lines the diagonal becomes the line joining the origin to the intersection points of the eqns. x + y = 1 and 6x + y = 3 respective;y. The intersection points aree: (2/5,3/5)...
Dear rutu, Given that AB=A AND BA=B. NOW B^2=BB =(BA)B =B(AB) (MATRIX MULTIPLICATION OBEYS ASSOCIATIVE LAW) =BA =B.
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