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Na + >Mg 2+ >Al 3+ >Si 4+
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for least ratio caation size must be small and anion size must be large so considering on the basis of this li is small cation and I is large anion so the answrr is b. LiI APPROVE IF USEFUL
Be2 does not exist because it has 4 electrons in valence shell and when we draw it molecular orbital diagram its bond order comes out to be 0 so it does not exist but i think in book answer given will...
sorry mansi correct answer for this question will be p-p > s-p > s-s typing mistake in previous answer this is due to extent of overlapping in p-p effective overlapping takes place so bond formed is...
ok thanx...i am doing ARIHANT complete success pakage for BITSAT 2015
yeah actually it should be c. becl2 exists as a dimer be2cl4 and hence involves co ordinate bond. dimerization of benzoic acid involves hydrogen bonding
PCL 5 is non polar bcoz it is symmetrical in shape
d)high sublimation energy of M according to hess law all the reactions take part in gaseous form high sublimation energy tells that that it will sublime in more time that is non effective of bond...
np level it get filled before (n-1)d bcoz np had high energy than that of d subshell and according to aufbau rule shell with more energy is filled first approve if useful
these books are good but in anurag mishra there is all type of questions that are asked in jee so i prefer anurag mishara for organic chemistry snsanyal is best for reagents and mechanisms and...
bonded electrons pairs that are present in octahedral SF 6 molecules will be 6 bcoz each fluorine atom is bonded to sulphur atoms in sf6 sulphur has 0 lone pair approve if useful
b. 1 bcoz Be and Al shows diagonal relationnship due to high charge density and high polarising power approve if useful
formula foe percentage of ionic character is 16x+3.5x^2 where x is electronegativity difference in ur que put x=0.5 and answer is 8.875 approve if useful
for max ionic character large size of cation and small size of anion so answer is CsF APPROVE IF USEFUL
B2H6 3 center bond 2 electron bond also called banana bond bcoz it flips very fastly and appear as banana approve if useful
hybridisation of boron in given compund is sp3 there is a easy method to determine hybridisation if valence electron if valence electron >8 then divide by 8 results on dividing 2 sp 3 sp2 4 sp3 5 sp3d...
in my opinion it may be polar covalent
acetylene i.e. C2H2 Ethyne, C 2 H 2 , has a triple bond between the two carbon atoms. In the diagram each line represents one pair of shared electrons. APPROVE IF USEFUL
there is no lone pair and the geometry is also symmetrical. So no dipole moment.
Sp2orbitals.Becausr MX3 molecule means it has 3bonds.so,to have a 0resultant dipole moment 3bonds are to be arrangedvectors so as to give 0dpmomnt. acc. to the triangle law of ele