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3/5sinx+4/5cosx=1 let cosA = 3/5 hence sinA=4/5 so now cosAsinx+sinAcosx=1 sin(A+x)= sin(pi/2) A + x = npi + (-1)^n pi/2
Let the perps from incentre I to BC, AB and AC be D, E and F resp. The FCDI is a square of side r. Then AF = AE = b-r (tangents from A to the incircle) and similarly, BD = BE = a-r. Then c= AB =...
Draw which is Isoceles as OB = OC. Now which means . Let D, be the foot of the perp from O on BC ( which is also the midpoint of BC). Then OD = OC sin (OBC) = R cos A. Hence the required ratio is cos ...
2sinA/cosA = 3sinB/cosBcross multiple2sinAcosB=3sinBcosA2{sin(A+B)+sin(A-B)}= 3{sin(A+B)+sin(B-A)}Solve furtherTry to put more efforts because trigonometry will not come until you give maximum 20...
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BD is the angular bisector and so by the property of angular bisector we have AD/CD = AB/BC. From the given info its clear that AD/CD = ½. Hence if AB = x, then BC = 2x. Now use Pythagoras to obtain
Momentum is like an energy (Be very catious, I don`t mean that its energy).When you give an object (say A) some momentum, you are acutally giving it some energy.You are changing it state of...
is similar to and is contracted by a factor of ½ (by BPT). So it suffices to find the medians of and double them. This way AD = 6 = BE and CF = are readily obtained
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Check the question once again, coz we need mini 3 numbers to tell whether its AP,GP or HP
HEY DEAR THE ANSWER IS ZERO. BECAUSE SON(0)=0 SO ANYTHING MULTIPLIED WITH ZERO GIVES ZERO SO ANSWER IS ZERO THANKS
hi imran sorry i didn’t mention alpha=0 ok proove that......................................................................................
friend please ask quations properly next time.dont ask this type of q..s again.i think you undastsnd,it is waste of time for us.
Dear student, cos 20`cos 40`cos 60`cos 80` *(8sin 20`/8 sin20`) =[4 (2 sin 20`cos 20`)cos 40`cos 60`cos 80`]/8 sin20` = [2 (2 sin 40`cos 40`)cos 60`cos 80`]/8 sin20` =[(2 sin 80`cos 80`)cos 60`]/8...
cos 20`cos 40`cos 60`cos 80` *(8sin 20`/8 sin20`) =[4 (2 sin 20`cos 20`)cos 40`cos 60`cos 80`]/8 sin20` = [2 (2 sin 40`cos 40`)cos 60`cos 80`]/8 sin20` =[(2 sin 80`cos 80`)cos 60`]/8 sin20` = [(sin...
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