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the polygon which has 11 sides is 11 sided polygon . and it is a useful polygon. it is a good polygon. it is used in analytical chemistry. from.. Chowdary.
the equation of common chord is s – s 1 = 0 equation of system of circles passing through the intersection of two circles is s + λ s 1 =0 the common chord is the diameter of the circle. so the centre ...
hi............ i think the answer is (1,2) because it is ellipse, ellipse general formulae is (x^2/a)+(y^/b)=1 from that eq. we got the answer
Dear student the graph will be smiliar to (<1)^x ka graph at x=0, y=1 at x=1, y=9/5 and so on
Find distance between the centres sqrt( r 1 2 +r 2 2 ) . Now you can any of the triangles to find out the half length of the chord
You need to have more information .Just this is not enough to find out the answer . Repost the question again and we will get back at you
Dear Student, Please refer to the below link for your answer. http://www.askiitians.com/iit-jee-coordinate-geometry/basic-concepts-of-ellipse.aspx Thanks.
parabola is symmetric in y axis with vertex at origin directrix is given by x+a,(a.0) is focus. Distance b/t focus&directrix is a+a/1=2a. now 2a=4&a=2,giving latus rectum 4*a=8
given (2,5) and (6,4). we know slope m= y 2 -y 1 / x 2 -x 1 by using that formula slope m=-1/4 thank you very much all the best
Not all you have to do but some part is good.and if you are going to 12 th Grade you can still afford little time for it. Its good for understanding but many question are irrelevant as far as JEE is...
Dear Student, Length of tangent common to both the circles will not be finite, it will be of infinite length. Thanks.
Dear Student, Its not clear what actually you want to ask, but any ways let me complete the above statment,Point of concurrency of chords subtending right angle at the vertex of parabola, then the...
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