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So anything wrong if m,n are integers with zero? Please be more specific.
Thank you so much Sir!!!
The centre will be (h,0). So the eqn will be (x-h) 2 + y 2 =52 This passes through (2,3) So will satisfy the eqn. Put the coordinates to find the value of h.
Hi student, The ans will D(zero) Because both the distances will be same only Pls refer the figure attahed which explains pair of conjugate diameters to hyperbola
Please elaborate the question. ............................................................................................................................................................
Please answer this soon....!
let eqn. of line be y-3=m(x-2), where m is slope of line dist. from origin = 3 I0-3-m(0-2)I/(1+m 2 ) 1/2 =3 solving we get , m=0 or -12/5 lines are y=0 or 5y+12x=39
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Form a family of straight lines passing through the point of intersection oflx+my+n=0 andpx+qy+r=0. (px+qy+r)+µ(lx+my+n)=0 Find the angle betweenlx+my+n=0 andpx+qy+r=0 and equate it to the angle...
Hey...its very easy. See, we know that for a triangle with vertices (x1,y1), (x2,y2) and (x3,y3) the centroid (h,k) is given as h = (x1+x2+x3)/3 and k = (y1+y2+y3)/3. Here we have all the three...
if you draw yhe diagram, and put C1,C2 the centre of circle with r=5. c3 the centre of circle of r=3. Since circle(c3) touch the both circle C 3 C 1 =C 3 C 1 -->C3 lies on perp. bisector of C1C2. let...
how you can say that they intersect at y=x , its for sure that they are symmmetric but i think its only a special case that they intersect at y=x.
it is a squre with line X=+a,-a Y=+a,-a
The lines 3x – 4y =0 and x+y=0 intersect each other at (0,0). Also the line 3x + 2y = 0 passes through (0,0) and is perpendicular to the third line 2x – 3y=7 . Therefore it passes through ORTHOCENTRE...
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