Click to Chat
1800 2000 838
Complete Your Registration (Step 2 of 2 )
View complete IIT JEE section
View Complete Medical section
Medical Exam Calendar
View complete NRI section
View complete study material
Be the first one to answer
Hello student, The equation of median through B is x+y = 5. The point B lies on it so the coordinates of B are (x 1 , 5-x 1 ) Now CF is a median through C, so coordiantes of F i.e. mid-point of AB are...
by daracharya’s method
Dear Student Method to Find The Equation Of The Angle Bisectors
Hello student, Since the line is parallel to z- axis so it has the direction vector as (0, 0, 1) Hence, the required equation is (1,1, 1)+t(0,0,1) = (1,1,1+t). so, x = 1, y = 1 and z = 1+t.
The given parabola isy 2 - 2y – 4x + 5 = 0. This can be rewritten as (y-1)2 = 4(x-1) Its parametric coordinates are x-1 = t 2 and y -1 = 2t and hence we have P(1 +t 2 , 1 + 2t) Hence, the...
Hello student, We understand your needs and appreciate the fact that you understand our situation as well. We try our level best to answer all the questiosn as soon as possible. But, at times due to...
Hello student, Let ABC be the given triangle and AD, BE and CF be the three altitudes. Now, to calculate the orthocentre, Step 1: Firstly, find the slopes of sides AB, BC and CA using the formula Step...
Hello student, Let P(x, y) be the required point on the parabola which is nearest to the focus. Then D = √(x – a) 2 + y 2 Now, y 2 = 4ax So , D = √(x - a) 2 + 4ax = √(x - a) 2...
Hello student, We are given that ∠ABC = 45° So, ∠BCH = 45° = ∠BCA 1 ∠C 1 CA 1 = 45° + 45° = 90° So, ∠C 1 B 1 A 1 = 90° Hence, the required angle ∠A 1 B...
Hello student, Given chord is ax – y + 7 = 0 and the parabola is x 2 = 28y. We first try to find out the points of intersection of the chord with the parabola as it would give us the end points...
If you feel that the above meathod is lengthy or complicated you can directly go from options by checking each option.
PLease find the answer in the image.
Let (x,y) be image of point (2,-1) (1,-4) will be mid point of (x,y) and (2,-1) x+2 = 2 y-1= -8 x=0 y= -7
The answer is Option C)12x-5y+2=0
d)(x+4) 2 +(y-3) 2 =16