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Hint: With the given 3 equaitons of lines of triangle, we can easily find the three coordinates of the triangle. Then by using the formula by determinant method, simply put the values of the three...
Hint: Count the number of times 5 occurs between 1 to 1000.
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Number of sides = 8.
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i always advise to use cengage series in math by g tewani this is the book will clear all the concepts in detail at advanced level but there are also a mainy of good books in math for advanced level...
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In this case angle(PQR)=120. So, bisector will make 60(=120/2) angle with PQ, which is -ve x-axis. So, bisector will make 120 (=180-60) angle with +ve x-axis
first write the equation of tan gent in slope form for both the parabolas i.e y=mx+a/m -1 and x=my+a/m -2 now compare the cofficients of x,y,m,a get the value of m and put in and get the answer which ...
Find the intersection of ax+by=1 with 2 lines, you will get two points, (1/(a-1) , -1/[b.(a-1)]) and (-(b+1)/[a.(b-1)] , 2/(b-1)), To prove two point say A(x1,y1) and B(x2,y2) subtend angle around...
Alternative solutions will be to use vectors, Let A(0,c). Assume side length=d. AC will be = (1-0) i +(2-c) j, Line AD can be in 1 st or 2 nd quardent, Point B = (0 i + c j) + d/rt(2) * (i + j),...
A circle with a radius cannot be inscribed in a square with side length a.
Hi, Its difficult to calculate the exact perimeter/ circumference of the ellipse. Hence there are many approximations to this formula. One such approximation is, Perimeter = 2*pi sqrt((a 2 + b 2 )/2)....
P = 2(l + b) 68 = 2(l + b) l + b = 34 d = 26 (l + b) 2 = 342 l 2 + b 2 + 2lb = 1156 l 2 + b 2 = d 2 (pythagoraus theorem) l 2 + b 2 = 26 2 = 676 676 + 2lb = 1156 2lb = 480 lb = 240 area = 240m 2
Understanding AP and GP will let you understand how the series can be solved easily which increases or decreases by the fixed ratio or distance. Thanks
The equation of a line will be 3x=2y. First integer point it will touch will be (2,3). From (0,0) to (2,3) it will cut 4 boxes. You can draw and check. This process will be repeated 2006 times as we...
c.10 (3,pi/4) will be in first quarter. (7,5pi/4) will be in third quarter. Just draw on graph. (3,pi/4), (0,0) and (7,5pi/4) will be on straight line. Hence distance = 3+7
y=mX+c, m=tan(150)=-tan(30)=-1/rt(3), put(0,0) point, |0-0-c|/(rt(1+m 2 )=10, c=+/-10rt(10)/3
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