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The vertex would lie between the focus and the foot of the perpendicular from the focus to the directrix. Find the foot of perpendicular from the focus to the directri. The vertex will be found by...
The 2 ends of the double ordinate will be meeting the parabola at P(c,d) and Q(c,-d). The line segments joining P and Q with the vertex will have slopes as negative reciprocals of each other. Find the...
Only equal chords subtend equal angles at the centre. Find the distance between centre of circle and the mid point of chord. The locus will be a circle woth same centre and radius equal to the the...
Hi Student x 2 + y 2 +2xy -16x + 16y +32= 0 (x+y) 2 = 16 (x-y -2) Put Y= x+y and X= x-y -2 Y 2 = 16X Which is required parabola Y=0 and X=0 will give vertex of parabola And the axis is given by Y=0 so...
b:parabola is ans. use A+B = 180-P then take tan and apply angle between lines formula. Assume A(a,0) B(-a,0)
Find the derivative of the hyperbola (even if it contains y). Find the slope at P and Q. Find their negative reciprocal. Those would be the slopes of the normals at P and Q. You have the slope and a...
Draw the 2 ellipse in the figure. At a point(take for instance (0,1) for convenience and symmtry), draw a tangent to the first ellipse cutting the second at 2 points. As we know the slpoe of tangent...
Length of perpendicular from a point (x1, y1) on a line ax+by+c=0 is the absolute value of : Use it to obtain the 3 perpendiculars and show that a1 2 = a 0 . a 2
Hello student, The point B you are talking abt is not specifid in the que pls specify Thanks...
Find the equation of the line which passes through the point of intersection of L1:2x – 3y + 5 = 0 and L2: 3x – 2y + 5 = 0, and also passes through the origin. Here’s one way to solve the problem. (i)...
Hello Student If you consider two triangles which are formed by the diagonal of the trapezium. In both the triangle base will be parallel to mid point of sides and both sides are also parallel hence...
Hello Student, Please post the full question again. Your question is not so clear. Thanks,...
Since none of the lines are perpendicular therefore it is not a right angled triangle. now find the intersection points of x+y=0, 3x+y-4=0, x+3y-4=0, we get (2,-2),(-2,2) & (1,1) let A(2,-2)...
Sir,Actually they are asking on which line x1,y1 lies :) ?
Please check the question and post it once again x 2 +y 2 =4 is not a eqn of ellipse...
Hello Student. Please find the solutionx+y+1=0 and x+y-1 are two parallel lines and distance between them is mod|\frac{1-(-1)}{\sqrt{2}} |So distabce between them is 2/root2 = root2So our req line us...
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