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Let the ratio be k:1 then point of division by section formula 3k+2÷k+1(x coordinate ) as this lie on y z plane hence x coordinate =0 K=-2÷3 hence it divides externally in the ration 2:3

just equate the ¾ vol of cone equals to the number of sphere x vol of a sphere you will get the answer almost 1.

The equation of circle through the intersection Of given two circles is S1+u(S2) where u is a arbitrary constant its value can be found by using condition of tangency

Just write the equation of tangent to the curve in slope point form for both the curves..as the tangent are common equate the y intercept to get values of m... Please post any question as it is...

Dear Student, Equaiton of any normal to y 2 = 4ax is y = mx -2am -am 3 . Now since it passes through (2,1) and a = 2. Therefore equation will be m 3 +2m+1 =0 Solve the cubic equation to get the number...

Find the eq of tangent from ellipse 1, then put the value of tangent in ellipse 2 . from there u will get the value of m and(x,y)

Let asume the centre of the circle be (h,k). Therefore its eq be (x-h) 2 +(y-k) 2 =25(s=0). Then make the eq of the circle by using the diametric form( using pt R(5,8),centre (h,k))is...

For conic section refer to SL lonely coordinate geometry as it covers all the topics with proofs for better understanding....but you have to skip some irrelevant topics

Dear Student, Your question seems to be incomplete. Please check it. Thanks.

Let the point be (h,k). So, already given that sum of distance of this point from two perpendicular lines in a plane is 1. Let those perpendicular lines are X-axis and Y-axis. Therefoe, |h| + |k| = 1 ...

Hint: 1. (i) Solve the two equations and get the intersecting points. (ii) Then apply the point form of tangent equation to get the equations of two tangents. (iii) Then find the solve of the two...

give up dont study giving up is the most important thing in the entire life i think youre just a dumb couh potato idiot …... who dont know anything ….... i thought i am the loser but you are bigger...

Equation of circle :4(x 2 +y 2 )=r 2 centre of the circle = (0, 0) equation of tangent :x=y+2 [y=x-2].....(i) slope of the tangent = 1 slope of radius = -1 using one-point form :(y-y 1 ) = m(x-x 1 )...

let the equation of the tangent y=mx (since c=0) putting y=mx in the eqn of parabola m^2x^2=4a(x-a) m^2x^2-4ax+4a^2=0 D=0 (since the tangent cuts the parabola at 1 pt...roots are equal)...

in my opinion you must try arihant intead of k.c.sinha... as it has proved to be one of the best books in market since many years

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