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The best books for above topics are ML Khanna and A Das Gupta. You can refer any one of them. Hope it helps. Thank You.
answer is (iv) because sum of supplementary angles is equal to a straight angle(180) but not greater than that.THANKS!!!
equation of side ac is x=2, so the point c has coordinates (2,k) and also distance between points a and c is equal to points b and c(since isosceles),so (k=5/2) and usng slope formula slope of bc is...
x=-1 and x=3 are touching the circle.so the midpoint of the perpendicular line joining these two lines will be the centre,but there are infinitely many lines.but also it touches y=3,so plot a...
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Let required circle be x2+y2+2gx+2fy=0---(1) Apply orthogonal condition (2gg'+2ff'=c+c') to above circle and to x2+y2-20x+4=0 We will get -20g=c+4---(2) Then apply perpendicular distance from centre...
LET THE THREE POINTS OF THE TRIANGLE AS A,B,C. LET ‘S(x,y,z)’ BE THE CIRCUM CENTRE OF THE TRIANGLE. TAKE AS=BS OR AS=CS AND SOLFOR x,y,z. TRY IT YOUR SELF AND POST IF U HAVE ANY FURTHER DOUBTS.
SOORY,I DON’T UNDERSTAND ,PLZ POST THE QUESTION WITH CLARITY. BYE HAVE A NICE DAY PLZ POST IF U HAVE ANY FURTHER DOUBTS.
Equation of normal y = mx – 2am – am 3 here a= 2 from parabola Passes through (2,1) 1= 2m – 4m – 2m 3 2m 3 + 2m + 1 =0 Derivate of above function is 6m 2 + 2 which is...
given A (3, 4) and B (7, 13). then P is the locus point then i.e P(x,y) we know that distance between two points root of (x 2 -x 1 ) 2 -(y 2 -y 1 ) 2 you just find PA+PB by usingabove eqation you...
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