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Due to less +I effect of one alkyl group there is less negative charge over oxygen atom hence primary alcohol easily loose H ion but in secondary alcohol due to greater + I effect of two alkyl groups...
well solomons and frhyle ( ms chauhan) will be nice . you can also have K s verma or ranjeet shahi (along with solomons and frhyle). then you gor for ms chauhan or himanshu pandey.
well you should go for K,s verma with l g wade. start with lg wade ( prefer topics within syllabus) and then ks verma .
CN is more important thanCHO IN presence of CHO ,CN acts as functional group so we have to consider CN as main functional group and CHO as substiuent
general organic chemistry is the topic if made strong enogh you can master organic chemistry..............................the method to study organic is not by learning but by understanding the...
In mechanism, the intermediate carbonium ion can be attacked by nuelcophile from either side. Soif the compound is optically active, then we get two compounds i.e compound with same configuration and ...
FIRST OF ALL LISTEN THE LESSON CAREFULLY WHILE THE TEACHER IS TEACHING . WE DONT REMEMBER IF WE STUDY ALSO.
SN2 IS SECOND ORDER REACTION IT IS FAVORABLE SECODERY CARBON THIS IS MY ANSWER YOU ASK ANOTHER QUETION
the enantiomers which are optically inactive are known as meso compounds.they ar optically inactive due to presence of plane of symmetry and also due to internal compensation
1S 2 2S 2 is the electronic configuration of the berillium compound it is the alkali earth metal berillium compounds are covalent compounds
The substance which has sour taste and acidic properties is known as ... Taste of orange juice is sour and sweet ... Citric Acid found in citrus fruits such as oranges and lemons etc . 2. ......
diazonium salt is reaction with cu or cl halide in the presence of hcl …and it forms constist freshely prepared diazonium salt solution with cuprous chloride...
vinyllic compunds are those in which
to wfind the simplest atomicity(emperical formula ) of a compound : first divide the % with its atomic no. you will get a decimal no. now take the least value among the two decimal and divide the...
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