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hey esha ...now tell me how it is non of these please
jitendra sir can you tell me how it is 0/0 form ….….…...no ther data is given....please
Ans: Let the resultant of vectors A & B to be C Angle b/w A & C Angle b/w B & C Or you can always say that the resultant will fall toward the vector which have more magnitude.
Ans: It is a simple quadratic function with root 3 & 4. Simply draw the graph of f(x) f(x) < 0 for 3 < x < 4 And similarly draw the graph of |f(x)| |f(x)| > 0 for 3 < x < 4 And...
Ans: It is a simple quadratic function. First, draw the graph of f(x). You will see, b/w 3 & 4, graph will lie below the x-axis. And the graph of |f(x)| will lie above x-axis b/w 3 & 4. And...
Ans: It is zero by zero form, apply L’Hospital Rule Hence, Proved
Ans:
Ans: For x > 50
Ans: Function log|x| is not defined at x = 0 So x = 0 is a point of discontinuity. Also for f(x) to be defined, Hence, 1 & -1 are pont of discontinuity. So there are 3 point of discontinuity {-1,...
Ans: Period of function: Given: There is no value of a for which above equation satisfy.
domain is all R, as the function is valid for all space R, but to find the range the f must be clear what the function f is , since the funciton f is not given it is not possible to give the answer.
[x]=x- frac(x)= x-x’ [y]=y-frac(y) =y-y\ [x][y]=(x- frac(x))(y-frac(y) ) xy- xy’- x’y-x’y’ = x+y xy- xy’- x’y-x’y’ – x- y is equation of...
Since syllabus of JEE Main Paper 2 Maths is same as JEE Main Paper 1. You can follow the following books: SL Loney: Trigonometry & Coordinate Geometry Hall Knight: Algebra IA Maron & Arihant:...
Syllabus of JEE Main Paper 2 Maths is same as JEE Main Paper 1 Maths. You can follow the following books: SL Loney: Trigonometry & Coordinate Geometry Hall Knight: Algebra IA Maron & Arihant:...
Let take the interval 0 to 2pi
Your basic concepts of differentiation should be very clear. You should know the slope of tangent & normal in differential form. Remember the formula for length pf tangent, subtangent, normal...
Ans: Yes, you can do by both ways. The one which is done in the question is easy & less confusing. You can do by directly putting the value of theta & use trigonometric identity
Ans: For limit to exist at x = 0,
No siddharth answer is not same check it bro
Thanx …........you are awesome sir …....you helped me whenever I required …..this website is awesome ….....
Ans: There is some little mistake in the expression Differentiete one time & apply the chain rule ….....(1) Put in (1)
Second step of answer please explain
Ans: Differentiate Differentiate
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