Click to Chat
0120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Be the first one to answer
This uses a technique called Differentiating under the integral sign. Consider the generalized problem of finding the integral This is a function of a. Now differentiating w.r.t a on both sides, we...
there are some functions for which you can not find the indefinite integration but there definite integral could be found. This is one of the example from those functions
from the terms of x^6, x^5 and x^4 take x^4 common it will make a quadratic equation and for the rest terms use common concept for solving. I hope this helps you in some way.
Vikas TU you are right, use by parts property of integration taking first term as sin(px) and 2 nd term as e^(-xy)
According to me you should try to put cosx = t and thus it will convert in simple integration of t^8, but remember to change to change the limits of the integration.
you can use the formula cosA*cosB=[ocs(A+B)+cos(A-B)]/2 and after that you can apply the concept of partial differentiation, it will make this question a lot easier.
The differentiation of the integeral, f(x)=∫ 2sinx-sin2x dx/x 3 would give f(x) simply. that is: lim x – > 0 (2sinx-sin2x) /x 3 Simply expand the exapnsion of sin terms up to the x^3 terms so...
I thin its volume. Volume of the solid sphere = 4/3 * pi* r3 put r = 4 and get the volume calculated itself in cm^3 for radii in cm.
Hi You can break it at all the integral points and then you can integrated this like shown in this image
This questions is from integration as a limit of sum This quantity is equivalent to Thanks
write sin(x-a) as: sin(x + a – 2a) = sin(x+a)cos2a – cos(x+a)sin2a then think further. and relate to √sin(x-a)/sin(x+a).
this was the answer...
let 1/x=d v then logx dx =v on integrating let tanx=u sec^2xdx=du ∫ udv = uv- ∫ vdu = logxtanx- ∫ logxsec^2xdx so ∫ tanx/x dx = logxtanx- ∫ logx sec^2xdx ------ (1) now consider the second term in...
Dear student Pls mention which quantity is gng from 0 toinfinity . Thanks
Hii try to divide it along any line passing through centre and then do the double integration of figure with respect to x and y . You will get answer in this case by this method
write x^3×cosx^3dx as: x*x^2*cosx^3dx => let x^2 = u 2xdx = du I = u*cos(u^(3/2)) Apply now by – part easily then after substitute u in the end.
use standard identities first and then reduc this to an easy expression eqn. then integearte it. Use, tan(A+B) = (tanA + tanB)/(1 – tanAtanB) tanAtanB = 1 – (tanA + tanB)/tan(A+B) for tan2x and tanx, ...
Detailed solution below------------------------------------------------------------------------------------- \quad \frac { 1 }{ 2 } \left( \frac { 1 }{ 2 } { tan }^{ 2 }\frac { x }{ 2 } +1 \right)...
solution below...
Please find the answer, this could be easily solved if you know differentaition of inverse trignometric functions
1388
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.