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U could easily break the integration in two parts ; when u would integrate this by using part function(Taking 1 as 2 nd function) , it will get cancelled(other part) and u would end up with THEN PUT...
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Hence the required ratio is...
You can use the integration by parts for that.Its First Function(Integration of IInd)- [(Integration {differentiation of Ist} {Integration of IInd} ].
Hey the ans is,-((A+Bcosx)^3)/bsinxThen substitute given value.And then eureka you got it.I didn`t substitute the value bcoz I can`t figure out the value of indefinite integration that you typed
@ vishal kindly tell me the full ques or the concept name in which u have problem . be little specific , i am not able to understand your query . else ,u can also attach the perticular ques in the...
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Above process is wrong , May be you mean
Please specify domain for this question otherwise it will be -infinity.
Setting log x = t, we can rewrite the integral as which by the formula for integration of e x [f(x)+f’(x)] is simply e x f(x) and hence is e t / 1+t i.e. x/(1+log x)
We can reduce the effort substantially...... This is easy to integrate
if x is positive, then f(x) becomes = > x^2 – 1 now this a parabola upwards with -1 as intercept. find the intersection points for gx and fx and tgen plot it on the graph. then integerate them from...
soln
Find ( sin2mx/sinx dx (definite integral) .. upper limit is 2 and lower limit is 3 … Thanks!/..
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