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sec2x=1/3x
(sin x2/2 / sin x5/5)dx
wh book 1s check it
use over here substitution let x+a=t and further solve plz aprve the then u could use by parts
here in the integrand we split it into 2 and integrate the only one part till u get the cancellable term and the then solve to get the answer
thank u i was just expanding the x cube +1 and forgot for the alternative of 1
u can write 1= x 2 -(x 2 -1) the then split it in to two and write x 3 +1 in the multiples of x+1 use the mehod of cancellation then partial diffrentiation and solve
here use invariance to get the solution send sinx inside and the the spread sin sq x in the 1- cos sq x and then multiply the then divide into 2 and then integrate
the then u could use by parts
look dsinx = cosx.dx therefore the final xpression will ne integrate d(sinx) the value would be sinx plz aprve
if we have a bigger expression then in that case we split the fiven function iinto two different function and then keep one of the function isolated and integrate the other by parts thus we will get...
GN berman IA maronrussian anthours best
u can use properties to solve the question or jacobi’s theorem
Integration by Substitution" (also called "u-substitution") is a method to find an integral , but only when it can be set up in a special way. When the integrand involves some trigonometric...
integration by parts is a theorem that relates the integral of a product of functions to the integral of their derivative and antiderivative. It is frequently used to transform the antiderivative of...
Indefinite integrals are also called general integrals. C is called constant of integration. All these integrals differ by a constant. From the geometric point of view, an indefinite integral is...
sin2A = 2sinA cosA cos2A = 2cos²A - 1 = 1 - 2sin²A ∫ sinx dx = -cosx + C ∫ cosx dx = sinx + C ∫ sin⁴x cos⁶x dx = ∫ sin⁴x cos⁴x cos²x dx = (1/16) ∫ 16 sin⁴x cos⁴x...
The given equation is: Let’s assume a general solution as: Therefore, we get: Therefore the general solution is:
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