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I will post it as soon as I can. I can`t find it at the present moment. Sorry! And thanks for your efforts.
Before you start a new project, you need to set up the development environment folder structure so that files with a similar purpose are in the same folder and are easy to find. For example, all...
Albert Einstein, in his theory of special relativity , determined that the laws of physics are the same for all non-accelerating observers, and he showed that the speed of light within a vacuum is the...
nitrogen gas , sulphur dioxide ,carbon monoxide , carbon dioxide. are some of the gases. well burning plastic is not good for living things. but there are many other things that are more harmfull so...
FORCE=PRESSURE X AREA FORCE=POWER/VELOCITY FORCE=IMPULSE/TIME FORCE=CHANGE IN MOMENTUM UPON TIME FORCE=WORK X DISPLACMENT FORCE=MASS X ACCELERATION FORCE=Kx (SPRING) FORCE=Kqq/R 2 (CHARGES) WELL THERE...
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Surface Tension formulae => Force = 4T/R 6.28 x 10^-4 = 4T/(2 x 10^-3) T= (2 x 10^-3)*(6.28 x 10^-4)/4 = 3.14 x 10^-7 N
The lower wire is uniform and therefore the Tension at the middle of the rope would be => 0.1 kg. The FBD of the lower block and the eqn. for that would be: => T – mg = ma or T = mg + ma => m(g +a) =>...
PRINCIPLE OF HOMOGENIETY just gives an idea in a way such that if the dimensions of terms in both sides are same or not. That means in the LHS and in the RHS terms they must posses same dimensions if...
0.5m(2Ve)^2 + GMm/R = GMm/r + 0.5m(V)^2 where r is tending to infinity. 2(Ve)^2 + GM/R = V^2/2 we get, V = root[2(2(Ve)^2 + GM/R))]
For small 8 droplets individuals the Pressure difference is: Pi – Po = 2T/r where r is the radii of the bubble. For one big drop formed by all the 8 equal droplets the pressure difference would be:...
Hello, Aparna I think the question needs a figure. Since I see no attacment plz attach an image to it with proper expalntion of qstn. The question is incomplete though! thnx!
Whenever there is a relative motion between the source of waves,medium and the observer,the frequency of waves received by the observer is different from the frequency of waves emitted by the...
Here the transmission of energy would takes olace b/w the whole system. Henc ewhen the lower chord igiven a jerk it transmits the energy to the mass as an impulse and hence to transmit the nrgy to the...
Mass of water from well => density x volume => 1*2238 gms or 2.238 Kg. Work = mgh => 2.238*10*20 => 447.6 J For height 10 m from the ground= > 2.238*10*10 => 223.8 J Net Energy required = > 447.6 –...
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