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From Young's modulus formulae, we get, Y = (F/A)/strain 10^20 = (855/(9.5 * 10^-4)(strain) strain = 855/(9.5 x 10^16) = 90 x 10^-16
500 = u^2*sin(2theta)/g................(1) and 10 = u^2*(sin(theta))^2/2g..................(2) solving both eqns. we get, ucos(theta) = 50 and usin(theta) = 50 we get u = root(5000) Maximum height =...
@ james its experimentally prooved , it have everything to do with energy . it is in the sense like +ve and -ve energy . opposite charges attract each other in order to complement the ;lack of...
coefficient of friction=acceleration of body \acceleration due to g happy to help u if u have any other question then send it to us
Let car A covered the distance as 'x’ meters then, x = 30*t.................(1) For car B, x = 0 + 0.5*2*t^2...............(2) solving both the eqns. we get, t^2 = 30t t (t – 30 ) = 0 t = 30 seconds.
The relation between van der waals gas and nonideal gas behavior : (P + an^2/V^2) (V – nb) = nRT a and b are constants .
Actual time to raach the bottom=> 19.6 = 0 + 0.5gt^2 t = root(3.92) = > 1.9798 seconds. Delta t = > 2.05 – 1.9798 = > 0.07010 seconds. v = 19.6/0.07010 = > 279.6 m/s.
@ honey no, not at all , a satelite is in a constant free fall motion . hence anything inside will feel the weightlessness . so, no g will act on the pendulum , so, we donot have any oscillations...
dear donga, On the top of mountain, value of ‘g’ is less. Period of oscillation,there period of oscillation increases and clock loses time.
dear donga, Since the sizes of metal bob and wooden bob are equal, the position of centre of mass does not change. Therefore the length of the pendulum remains same so, time period remains constant.
dear donga, If water begins to drain out of the hollow sphere, its centre of mass begins to shift below the centre of the sphere. Hence the length of the pendulum increases and time period also...
dear donga, When the girl stands up, her centre of mass moves up and length of swing decreases. Hence frequency of oscillation increases.............
dear donga, 1) Motion of the seconds hand in a function function watch. 2) Revolution earth around the sun.
dear peter, A pendulum with time period 2 seconds is called second pendulum. Its length on earth is 100 cm.….….….….…....
dear peter, Phase is that which denotes the state of vibration….….….….….….….….….….….….….….…. ….….….….….….….….….….….…..
dear peter, The number of oscillations completed by a particle in one second is called frequency...............................................................
dear peter, The time taken for one oscillation is called time period...........................................................................................
Given, E = k/x^2 icap dV/dx = -k * x^-2 dV = -kx^-2 dx Integerating both sides we get, V = k/x limit frm V to O and k/2 to K we get, V – O = (2 -1 ) V = O + 1
Satellite will move tangentially to original orbit with same velocity by priyanshu jha @ bihar.......................
This is because the formula must contain per sec in it
Power is constant hence, a = (6-3)/t = 3/t m/s^2 (change in velocity) From 2 nd law of eqn. we get, 252 = 3*t + 0.5*(3/t)*t^2 252 = 3t + 1.5t t = 252/4.5 t= 56 s
Pt = Pa + Pb Pa = Xa*Pt Pb = (1 – Xa)*Pt Now moles of the gaes are: 60/20 => 3 moles and 124/32 = 4 moles respectively. Mole fraction of Ne gas = > 3/(3 + 4) = 3/7 = Xa Putting in Pa and Pb we get,...
Dear Vani, U have forgot to attach the image/figure. I suppose U to re-post the qstn. with the attachment plz. Thankyou!
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