JEE Advanced
JEE Main
BITSAT
View complete IIT JEE section
AIPMT
AIIMS
NTSE
KVPY
Olympiads
CBSE
ICSE
UAE
Saudi Arabia
Qatar
Oman
Bahrain
Kuwait
Indonesia
Malaysia
Singapore
Uganda
View complete NRI section
Physics
Chemistry
Maths
Revision notes
View complete study material
Buy IIT JEE/AIPMT study material
Buy CBSE Grade 8/9/10 study material
See, the electric field inside the conducting sphere is zero because no charge resides inside its surface. So, by the expression, E = -∂V/∂R V is constant since E is zero. Thus, it will have the same...
Be the first one to answer
p { margin-bottom: 0.25cm; line-height: 120%; }p { margin-bottom: 0.25cm; line-height: 120%; } Dear student, please see the picture below. p { margin-bottom: 0.25cm; line-height: 120%; } Let =...
The gravitational force on the oil drop = mg = 3 x 10 -16 x 10 = 3 x 10 -15 N. Magnitude of the electrostatic force needed balance this force is given by E = mg/10e = (3 x 10 -15 ) / (10 x 1.6 x 10...
p { margin-bottom: 0.25cm; line-height: 120%; } Potential due to a spherical charge distribution at distance r 1 is given by Magnitude of electric field due to spherical charge distribution at...
This question belongs to Mechanics thread. It is answered there. However, I have reproduced the same below: We can use law of conservation of angular momentum and law of conservation of mechanical...
Since, the radius is 1.64 mm i.e. r = 1.64 x 10 -6 m As we know, m=∂*v (where ∂ is density and v is volume) therefore, m = 0.851 x 4/3-pi-r 3 = 1.45 x 10 -17 kg We have already studued that qE= mg...
Since, the charge density of line is 1micro coulomb, i.e. it can be written as 10 -6 C . and radius=1cm =0.01m Now, Electric Field E= ∂/2-pi-epsilon naught-r where, ∂ is linear charge density and r is...
By symmetry net electic field along X-axis at the centre O is zero and electric field along Y-axis will be added up. dE Y =1/4pi-epsilon-naught x dq/r 2 sin@ but dq= ∂(rd@)=q/pi-r x (rd@) = q/pi d@...
p { margin-bottom: 0.25cm; line-height: 120%; } Ooops... there is a small mistake in the diagram. The vector showing the moment of charge –q should point in opposite direction.
correct option is 4.
“... consisting of 2 ncharged charges capacitors ….” is being interpreted as “ consisting of 2 uncharged capacitors” Intial potential difference across 1uF capacitor C1 is V o = 110 V. When the...
ohhhhhhhhhhhhhhhhhhhhhh …. i have solved this type of question ,, by symmetry we take half charge inside and half charge outside .. now solve to get your answer q/2e 0.. thanks
Hi, Find the expression of the force of repulsion between the two charges in terms of q. F = k q(Q-q) / r2 To get maxmum value of force, dF/dq = 0, So, (k/r2) (Q – 2q) = 0 or q = Q/2...
Hi, Coulombic force, F = k q2r^ / r2 r^ = (r2– r1)/ r =(i + 2j – 2k) / 3 Now, put this value of r^ in the force equation to get the force vector. The ‘i’ component of the force...
In this case, first you calculate the flux through cube, it would be sum of flux through the one surface and flux through the rest. Flux through the cube wil be q/8Ç,= 3xFlux through one wall +...
Hi Student, Please in detail explain your...
The flow of charge depends on potential difference and is in turn depends on capacitance, as potential difference varies exponentially wrt time, it theoratically takes infinite time.
Hi, Yes, it would travel in the straight line but with variable acceleration depending on its position in the electric field....
Hi, If you have looked at the question carefully, all the four branches are between ponts A and B. Two branches have capacitance C/2 (C and C in series) each and other two branches have capacitance C...
Ceq is 2C
The 5 capacitances in the mid are forming a wheatstone bridge. So, if a test battery were to be applied, the curent wouldn’t pass through the vertical C in the middle as it is a balanced...
The option is (2) equate both of them to equal potential to get the answer.
Dear student, According to the question, 10 9 electrons move out in 1 sec. So, the charge transferred per unit sec is equal to so, to transfer 1 C charge, the time taken would be equal to Regards
Hi, Two similar charges are stable when they are far away, but when they are brought closer, they become unstable due to increase in potential energy (+ve) But when two unlike charges are brought...
1249