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http://www.askiitians.com/iit-jee/advanced/important-books.html The above link provides a list of useful books that can be used together to clear concepts in physics.
I found your problem similar to me ,when i was at this stage. What i did was first i tried to clear my concept because physics is all about clearing concepts and reading the theory by heart. I...
charge density=q/4(3.14)r=Q/4(3.14)R. ie, q=Q*r*r/R*R. potential at center of shell=kq/r+kQ/R kQ/R(r/R+1) Q=charge density*4(3.14)R*R on simpilfying, V=charge density*(r+R)/epsilon
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As an electrical storm builds, various mechanisms create a stratified charge within the storm cloud, with an electrical charge at the base of the cloud. Since we are mostly concerned with...
Hii Yeah if you can represent the voltage in terms of radius and you will get the answer
It is not practical to discuss about potential,when field is zero.For example, if you are bald person(ie,if you don’t have any hair), then it is useless of talking about your hair style!!!!. Thus,...
repulsive electrostatic force: attractive gravitational force: F 1 =kQ^2/r^2 F 2 =Gm^2/r^2 for equilibrium :F 1= F 2 kQ 2 /r 2 =Gm 2 /r 2 => Q/m = (6.6*10^-11/9*10^9) 1/2 => Q/m=0.8*10 -10 Hence,...
Whats the difficulty first find out that what are the differnt forces acting on the small sphere (i.e. electric force mg and tension making an angle theta with the vertical) then resolve it into...
According to gauss law, flux through a closed surface=q/(epsilon). Here charge enclosed by hemisphere=q/2 therefore, flux =q/2(epsilon) .
[electrostatic potential energy]=[charge]*[potential difference] [joule/coulomb]=[potential difference]. [M L^2 A^-1 T^-3].answer
Force eperienced by the particle=kq1q2/r^2 =k*1*(10^-6)*2*(10^-3)/1 =18 N. acceleration of particle=f/m=18/1*(10^-3) a=18000m/s^2. since V^2=U^2+2*a*S, Initial velocity of particle=0 m/s, thus,...
hello sahil we take cos instead of sin because we are doing dot product. in dot product we take cos and in cross product we take sin. for this you had to study the topic vector multiplication regards ...
Hey student.. please clarify the subject u r refering to
Use formula for line of charge but use q/l instead of lamda. The distance from the line will be equal always as radius is constant
force experienced by it will be zero. as F=qE,as net electric field inside the shell is zero(provided it’s metallic),because the electrons rearrange themselves and cancel out the field produced...
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