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If the Gaussioan surface would pass through the dicrete charge then there would be a contradiction with what part of chrge would be considered inside the surface that is to say that Electric field...
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@ aamina No , gravitational field is the field which is acts by the earth or some heavenly object on a body . but electric field is the field that will act when the charge will be their . and they...
@ shreyas the derivation of electrostatics are usually based on assumption . as u need to know the correct position of charged particle and the coordinate system . steps of learning derivation 1-...
whats the answer? is it....... 2C Because as you can see that the lower part forms wheatstone so middle part is removed. So, in rest of the figure upper part of C is in paralle with the middle part...
the reason is due to loosely boundation of elctrons in metals/conductors which are scattered on the surface. thus a limited excitation of the conductor even leads the electons comes on to the surface ...
Gravity force = Gm1m2/r^2 and Electric Forces = kq^2/r^2 divide them to get the ratio after puttundg the values of their known masses and charge. r would get cancelled.
Let thre is x voltage at the junction of four branches. Apply KCL there and find x. After that write the current (potential differnce eqn. in capacitor branch} that would be: x – 8i – (1/C)∫idt – 10...
E at point P-> => due to -ve cahrge => kQ/(a^2 +d^2) {attracting} => due to +ve charges => KQ/a^2 + kQ/(a^2+d^2) Now components them in horizontal and vertcial direcn. after finding the angles in...
i think the answer should be 1 divide by epsioln not. 1/e = 1.13 x 10^-11 Nm^2/C. this is according to the Gauss’s Law.
due to covalent bond b/w them charge on an atom is less than the quantum no of charge and the atoms sharing ionic bond have quantum no. of charges which are way too stronger than covalent bond.
The partial charge is the non – integer chrge which we also enotes by delta positive or negative charge which is seen in HCl rather thant qunatum charge. And that is smaller thanquantuum chrge as the ...
e = 100,00,00,000 c = 100,00,00,000*1.602*10^-19 q = 1.602*10^-10 i = q/t t = 1 micro sec i = 1.602*10^-10/1*10^-6 i = 1.602*10^-4
@ dhanush its beacuse of the following reason 1- when an airplane lands or takes off there is much friction between the tyre and the road which might lead to accumlation of charge in the tyre . 2- in ...
@ rohit your questions are not clear also the image , kindly upload a clear image without that uc browser tagup . thats blocking the question as well as its figure . but , as per my understanding , i ...
Because Charges are quantized. And the proton itself can decay to positron wgich is enough idea to proove that they must posses diffenent mass but similar charge.
E = -dV/dx dV = -Edx integerating both sides we get, V = – Ex = > -Abx = > – 10bx {put limit from 20 to 10} and get V.
charge stored in capacitor decreases due to its decay. Q = CVe^-(t/RC). Dut to this decreasing in minus of t/Rc with increasing time the the charge exponentially decreases).
Total charge given for loop = q. Charge per unit length = q/2*pi*R for dl element, dq = qdl/2*pi*a. Net electricf field at center due to that small length and reaining is: 0 = E + kdq/r^2 thus just...
64*(4/3 pi r^3) = (4/3 pi R^3) R = 4r Potential of bigger sphere, k64q/R => 16(kq/r) = >16*10 = 160 volt.
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