JEE Advanced
JEE Main
BITSAT
View complete IIT JEE section
NTSE
KVPY
Olympiads
CBSE
CISCE
UAE
Saudi Arabia
Qatar
Kuwait
Oman
Bahrain
View complete NRI section
Physics
Chemistry
Maths
Revision notes
View complete study material
Buy IIT JEE/AIPMT study material
Buy CBSE Grade 8/9/10 study material
Be the first one to answer
abe answer to mujhe bhi pata he mujhe soln chahiye
(C/3) + (C) = 4C/3 { [1÷(4C/3)] + [1÷C] } -1 = {7/4C} -1 = 4C/7 (4C/7)×2 = 8C/7 (due to symmetry multiplication is done)
Solid angle dw = dA cos Theta / R2 For hemisphere surface area will be half so the solid angle will be 2 pi at an external point its unit is steradian dw = 2piR 2 cos 0 / R 2 = 2 pi steradian...
It will not feel any electrostatic force becuase inside the metal block is cavity. so will not be any electric field hence it will not experince any electrostatic force since charge distributed on the...
When Negative charge is given to the soap bubble then it will distribute over the surface and at each point there will be electrostatic force. it will repel each other until restoring force due to...
To find the Net electric field we take a vector some of all electric fields. Electric field has a vector nature.The magnitude or strength of an electric field in the space surrounding a source charge...
One characteristic of a conductor at electrostatic equilibrium is that the electric field a charged conductor is zero. If an electric field did exist and inside the conductor then the electric field...
Yash Pungalia, your answer is correct , but can you please explain how?
The charge q wouldn’t feel any electric force as medium of separation being metal because relative permitivity of metal is infinity so the force between Q and q is 0
Thanks for ur answer. It is a good answer.I Really appreciate that.
ASSUME THAT THE ENTIRE CHARGE OF THE TWO CONES IS CONCENTRATED AT THEIR CENTRE OF CHARGE(SAME AS CENTRE OF MASS) i.e DISTANCE BETWEEN THE TWO CHARGES IS 2x3H/4=3H/2 AND TOTAL CHARGE (MAGNITUDALLY) BE...
Dear student, The equipotential surface would be given by: For this surface to be equipotential, the potential is a constant, hence, So the correct option is option (c0. Regards Sumit
using A.M-G.M inequality: for maximum force between two charges q(Q-q) should be maximum accordingly q=Q-q ie 2q=Q or q/Q=1/2. WITH REGARDS SIDDHARTH GUPTA
for a simple pendulum, T=2#(l/g)^1/2 force experienced by charge=qE accl=F/m=qE/m , time period=2pi(mL/qE)^1/2
The dipole is pair of two equal and opposite charges so field due to it represents the vector sum of filed due to bothe the charges, but from one charge it is a single field.
1215