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Because when the aeroplane lands on ground then the aeroplane has very high speed which produced maximum amount of fraction . Fraction create electric current,if the tyre is made of insulator,tyres...
dear kp if inner surface is grounded Then (Q1+Q2)/2 charge will appear on outer surfaces of both and inner surfaces will have no charge. if outer surface is grounded Charge on outer of both=0...
dear pragnya kindly let me know about which exam u are talking about ?? 12 th board or iitjee , so, that i can tell you what to do to get the maximum output within minimum time limit , WAITING TO HEAR...
HEY DEAR THEY WILL EXPERIENCE SAME FORCE BUT NOT SAME ACCELERATION BECAUSE F-qE WHERE q IS CHARGE WHICH IS SAME FOR BOTH PARTICLE AND E IS ELECTRIC FIELD WHICH IS ALSO SAME HENCE FORCE ON BOTH...
Hy kapil.. Yes they will experience same electric force but the direction of application of force will be opposite for them.. But their acceleration are different as acceleration also depends on mass...
calculate the distance travelled by the charge using coordinate geomentry and calculate force between charges using by differentiation and then integeration.then find work done as w=f.s.
From gauss law we know that the electric fluxes passing through a closed surface is directly proportional to the charges contained in the surface... From your fig it is clear that charge inside...
As the whole system is placed at ground the circuit becomes closed loop and hence from KVL, V – Ldi/dt – V’ = 0 V = Ldi/dt + V’ kq/r = Ldi/dt + 0 (initially) kq/r = L*d^2q/dt^2 Ld^2q = (kq/rL)dt^2...
Volume would be conserved. Hence, V =nv 4/3*pi * R^3 = n*4/3*pi*r^3 R^3 = n*r^3...........(1) And as charge is a scalar quantity, Q = nq......(2) From both eqns. we get, Volt = KQ/R => Knq/(rn^(1/3))...
Hi Ijas, you can use V=Ed i.e. potential diff between the plates is distance times the electric field between them. V=150-(-50)=200, d=2cm = 0.02m , therefore , 200= E*0.02 =>E=10 4 V/m please approve...
The system will be equivalent to two identical capacitors connected in series in which two plates have separation half the original separation. So new capacitance--- c`=2cAs c is inversely...
It follows this simple equation: neutral + neutral= neutral. In P type semiconductor, we simply replaced some silicon atoms and put some trivalent atoms(say Boron) in place of them.Now, in the process...
Let the initial charge on B and C is q, After third sphere comes in contact with B then new charge on B and the third conductor would be =q/2 and third conductor come in contact with C so total charge...
Force b/w -8q and Q would be: F1 = k(8q)Q/x^2...............(1) Force b/w +2q and Q would be: F2 = k(2q)Q/(L +x)^2..............(2) F1 = F2 8/x^2 = 2/(L+x)^2 4(L+x)^2 = x^2 (2L + 2x – x) (2L + 2x +x)...
Because Capictor has the power to store chrge only if only meeting the required conditions of cpacitor formed. There should be two atleaset insulating non conducting material b/w the the chrge would...
Potential at origin would be: Vnet = Kq(1/1 + ½ + 1/4+ 1/8 + ….....+ infinity) = Kq((1/(1-1/2)) = > 2Kq For opposite side the potential would remain same as the distance would be constant and hence...
dear srikant the electric potential inside will be = Kqr / R ^3 where k = 9 * 10 ^ 9 the electric potential on the surface will be = Kq / r ^ 2 HOPE IT CLEARS NOW REGARDS
I think we can apply here, the concept of image charges. Just put a charge a -q1 with q2 so that there will be two charges q1 and (q2-q1) at a separation R. Now apply columb`s law.If the above method...
EF strenght on p2 due to p1 is E = -2kp2 / r^3 hence force F = p2 * dE/dr = -6kp1p2/r^4 Thanks
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