JEE Main 2025 Results: Toppers and Trends

 

JEE Main 2025 result for Session 1 (conducted from 27 January to 1 February 2025) – Paper 1 (for BE or B.Tech) – was declared online on February 12, 2025. More than 11.7 lakh engineering aspirants registered for the paper, and around 10.7 lakh candidates wrote the exam. The exam was conducted in 544 examination centers in 319 cities, including 22 cities outside India.

 

Students could check results on three websites:

  • jeemain.nta.nic.in
  • nta.ac.in
  • ntaresults.nic.in

 

They had to click the direct link for the JEE Main 2025 result, key in their login details, download the scorecard, and print it for future use.

 

Those who scored around 267 (out of a total of 300 marks) were placed in the 99.95+ percentile. Candidates scoring 270 were around the 99.99 percentile mark. Those who scored around 290 typically fell in the 99.996 percentile range, and a perfect score of 300 usually fetched percentiles between 99.998 and 100.

 

 

S. No.

Name of the Candidate

State to which they belong

1


Andhra Pradesh


Shaik Suraj



2

Jyotishman Saikia

Assam

3

Aarav Bhatt

Haryana

4

Rajbeer Singh

Jharkhand

5

Amogh Agrawal

Karnataka

6

Anirudh Kant Garg

Punjab

7

Ishaan Gupta

Rajasthan

8

Jasti Yashwant VVS 

Telangana 

9

Rishi Shekher Shukla




10

Bhavya Tiwari

Uttar Pradesh

Four of these toppers with perfect marks were from Telangana, and three were from Andhra Pradesh.

 

State-wise Toppers for NTA JEE Main Advanced 2022 Session 1 Exam

 

S.No.

State/UT

Name of the Candidate

NTA Score or Percentile

1

Andaman & Nicobar Islands

Sanjay Sanish

98.4368262

2

Andhra Pradesh

Shaik Suraj

100

3



4



5

Arunachal Pradesh

Vinnakota Sneha Naga Sanjana

99.4251648

6

Assam 

Jyotishman Saikia

99.9291797

7

Bihar 

Abubakar Siddique

99.9923205

8

Chandigarh 

Ayush Gangal

99.9991763

9

Chhattisgarh 

Aarav Singhal

99.9722531

10

Dadra & Nagar Haveli 

Shah Aryan

99.1407483

11

Daman & Diu 

Hatker Preet Mahesh

97.3956257

12

Delhi (NCT) 

Madhav Bansal

100

13



14

Goa 

Navinya Devanand Desai

99.8821804

15

Gujarat 

Parekh Meet Vikrambhai

100

16

Haryana 

Aarav Bhatt

100

17

Himachal Pradesh 

Amrit Kaushal

99.7469472

18

Jammu & Kashmir 

Sushant Padha

99.9775041

19

Jharkhand 

Rajbeer Singh

99.9878607

20

Karnataka 

Amogh Agrawal

100

21

Kerala 

Jithin J Joshi

99.992392

22

Ladakh 

Padma Rigzin

96.363698

23

Lakshadweep 

Dnyanada Sunil Limbale

94.5520602

24

Madhya Pradesh 

Aditya Pratap Singh Bhadoria

99.9983415

25

Maharashtra 

Gajare Nilkrishna Nirmalkumar

100

26

Manipur 

Rohan Singh Leishangthem

98.536627

27

Meghalaya 

Abhijnan Saraswat Gogoi

98.0996296

28

Mizoram 

John Laldingliana

93.6225375

29

Nagaland 

Md Siddek Ahmed Choudhury

98.8762319

30

Odisha 

Satyendu Kar

99.9839386

31

Puducherry 

M Balakumaran

99.9005378

32

Punjab 

Anirudh Kant Garg

99.9991524

33

Rajasthan 

Ishaan Gupta

100

34

Sikkim 

Priansh Yajnik 

99.9462403

35

Tamil Nadu 

Mukunth Prathish S

100

36

Telangana 

 

Rishi Shekher Shukla

100

37



38



39



40

Tripura 

Antareep Ray

99.8213201

41

Uttar Pradesh 

Bhavya Tiwari

99.9966033

42

Uttarakhand 

Shivam Agarwal

99.9694856

43

West Bengal

Irradri Basu Khaund

99.9934104

 

Category-wise merit lists are also declared.

 

How to calculate the NTA score or percentile score of a candidate?

 

NTA score is not the exact percentage of marks candidates obtain in the JEE Main exam. The exact marks are called raw scores. To calculate the NTA score or percentile of a candidate:

 

NTA Score or Percentile = 

100 X No. of candidates who scored equal to or less than specified marks

Total no. of candidates appeared in the JEE Main Session 1 exam

 

Once the results of both the sessions of the JEE Main exam are released, the AIR (All India Ranks) of candidates will be declared based on the NTA scores of candidates of both sessions. For example, in 2025, Session 2 of the JEE Main exam was conducted in April, and the result is expected to be released shortly after the exam concludes.

 

Frequently Asked Questions

 

  1. What are the opening and closing ranks for IITs?
    Admission to B.Tech programs in IITs is done on the basis of All India Ranks (AIR) of candidates in the JEE Advanced exam. They will be declared after the JEE Advanced 2025 exam is conducted and its results are declared. The opening and closing ranks for admission to various B.Tech courses offered by IITs change every year.
     
  2. What are the minimum marks required for admission to NITs, CFTIs, and other engineering colleges?
    Earlier, candidates had to obtain at least 75% marks in the Class 12 exam (or be in the top 20 percentile in the Class 12 exam) to be eligible for the JEE Main exam. NTA has removed this criterion now. The minimum marks required for admission to NITs, CFTIs, and other engineering colleges are based on the final NTA merit list.
     
  3. What are the changes introduced in JEE Main 2022?
    The key changes of the JEE Main exam in recent years include the introduction of negative marking for Section B questions as well. Section B contains numerical value questions, and earlier, only Section A, which contained multiple-choice questions (MCQs), had negative markings.
    Now, there is a penalty of 1 mark for each incorrect answer (1 mark gets subtracted from the total score of the student) in both sections.
    For JEE Main 2025, students can choose their exam center cities from anywhere in India while filling out the form, offering greater flexibility compared to earlier years when students were limited to selecting centers from their state of present or permanent address. Also, candidates will be allowed to make corrections in their JEE Main application form during the specified correction window after submission.
     
  4. What is the syllabus of JEE Main?The syllabus of JEE Main is prescribed by NTA and is based on Class 11 and 12 Physics, Chemistry, and Mathematics topics. Candidates can check the detailed JEE Main syllabus here.
     
  5. How can I become a JEE Main topper?
    There is no shortcut or magic formula to become a JEE Main topper. Candidates must focus on their Class 11 and 12 studies and be aware of the topics included in the JEE Main syllabus. They must also solve as many JEE Main mock tests and previous year papers as possible to get familiar with the exam pattern, types of questions asked, and the level of difficulty.
    AskIITians offers rigorous 1-year and 2-year programs for students appearing for the JEE Main exam. These programs are designed by ex-IITians and experienced faculty who have helped thousands of students prepare for the engineering entrance exam.