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Find the maximum and minimum value of
(sin x)^2 + 4 cos 2x for x belongs to R
Dear Karthik,
cos2x = 1- 2sin2x
so, (sin x)^2 + 4 cos 2x = 4 - 7sin2x
Max. value = 4 put sinx = 0
Min. value = 4 - 7 = -3 at sinx = -1 or 1
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