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How the volume occupied by 1 mole atom of diatomic gas at NTP will be 11.2 litres?
Dear Chanchal,
Mole = Volume/22.4 (At S.T.P or N.T.P.)
so according to this formula 1 Mole of gas occupies 22.4 litres at N.T.P.
suuppose diatomic gas is O2
1 mole of O2 gas occupies 22.4 lit at N.T.P.
since O2 consist of two atoms means 1 mole of O2 contains 2 mole atom of oxygen.
thus we can say since 1 mole of O2 or 2 mole atoms of oxygen occupies = 22.4 litres at N.T.P.
therefore 1 mole atom of oxygen occupies = 22.4/2 = 11.2 litres at N.T.P.
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YOUR NAME
ABHISHEK JAIN
AskiitiansExpert-IITD
Its like that.
1 mole of diatomic gas at STP or NTP=22.4L
this means 2*(i mole of atom not molecule)=22.4
=> 1 mole atom(not molecule)=22.4/2
=11.2 litre.
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