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Chanchal Kumar Grade: 11
        

How the volume occupied by 1 mole atom of diatomic gas at NTP will be 11.2 litres?

6 years ago

Answers : (5)

ABHISHEK JAIN AskiitiansExpert-IITD
20 Points
										

Dear Chanchal,


  Mole = Volume/22.4 (At S.T.P or N.T.P.)


so according to this formula 1 Mole of gas occupies 22.4 litres at N.T.P.


 


suuppose diatomic gas is O2


 1 mole of O2 gas occupies  22.4 lit at N.T.P.


since O2 consist of two atoms means 1 mole of O2 contains 2 mole atom of oxygen.


thus we can say since 1 mole of O2 or 2 mole atoms of oxygen occupies = 22.4 litres at N.T.P.


therefore 1 mole atom of oxygen occupies = 22.4/2 = 11.2 litres at N.T.P.


 


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ABHISHEK JAIN


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6 years ago
Rohit Singh
33 Points
										

Its like that.


1 mole of diatomic gas at STP or NTP=22.4L


this means 2*(i mole of atom not molecule)=22.4


=> 1 mole atom(not molecule)=22.4/2


=11.2 litre.

6 years ago
suresh
22 Points
										
why one mole gas is having same volume at stp and ntp, both are not same temperatures. according to charles law, v is proportionl to volume.
2 years ago
suresh
22 Points
										
why one mole gas is having same volume at stp and ntp, both are not same temperatures. according to charles law, v is proportionl to temperature
2 years ago
Bhawani shankar Sahu
32 Points
										
actually the volume at NTP and STP are not equal. at STP the volume of 1 mole of gas is 22.4 lt but at NTP the volume is 24.02 lt.  you can derive this from PV=nRT
10 months ago
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