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Aditya Nijampurkar Grade: 12
```        The 2.7 kg cylinder B and 1.8 kg wedge A are released from a bigger triangular wedge A wich is fixed. the angle of inclination of A is 30 degrees frm the horizontal.Assuming that cylinder rolls without sliding on the wedge and neglecting the fricyion between a and c determine
(a) the acceleration of wedge
(b) the angular acceleration of cylinder
(g=10m/s^2)

```
7 years ago

## Answers : (1)

Chetan Mandayam Nayakar
312 Points
```										Dear Aditya,
acceleration of wedge=Mwgsin(30)/M=5m/s^2
a=linear acceleration,A=angular acceleration,f=friction,r=radius of cylinder,m=mass
a=rA, ma=mgsin(30)-f,fr=(1/2)mr2A, solving the three simultaneous equations we get a=(2/3)gsin(30)=10/3 m/s^2
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Chetan Mandayam Nayakar – IIT Madras
```
7 years ago
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