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Well I also think that it is incomplete
The initial conditions are not given
Are they at rest?
If yes then
The v of COM remains unchanged = 0
Dear Hemant
Question is correct
suppose particles(m and 3m) are placed at some distance r. take origin at m
position of centre of mass= m*0+3m*r/4m = 3r/4 from m
now if they start moving then from action reaction force on both will be same but due to mass difference acceleration will not be same. if acc of m is a then acc of 3m will be a/3. so there will be relative acceleration they will move towards each other with relative acc of 4a/3 and the value of a will not be constant. as gravitational force is proportioal to 1/r2 hence a is also proportional to 1/r2. centre of mass will also change its position as both move with diff acc and diff velocity.
so please confirm the question that is the force constant or v=2m/s is at what instant.
All the best.
AKASH GOYAL
AskiitiansExpert-IIT Delhi
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Dear student,
Here concept of reduced mass wll be used..
Mr=m1m1/m1+m2
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Sagar Singh
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