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A ball is projected from a point 45m high, along the horizontal with speed 20m/s. if the ball perpendicularly strikes a plane inclined at angle theta with the horizontal. find tan(theta) [g=10m/s2 ]
dear chaitanya,
As the projectile is projected , the horizontal or the y component remains the same ( we have neglected air resistance )
but the x component will increase due to acc due to gravity,
therefore , v2 = u2 + 2as
u=0
a=10m/s2
s=45 m
therefore v= 30 m/s ,
as we know that tan(theta) = v(along y component) / v( along x component)
tan(theta) = -2/3
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