MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
VISHAL KEJRIWAL Grade: 12
        HC Verma , Exercise question no. 28?
7 years ago

Answers : (2)

Vijay Luxmi Askiitiansexpert
357 Points
										

Dear Vishal,


Please post the query here on the forum..


We are all IITians and here to help you in your IIT JEE preparation.

All the best.


 


Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.


Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar : Click here to download the toolbar..




Regards



Askiitians Expert


Vijay Luxmi


7 years ago
priyank sharma
37 Points
										

applying cons. of momentum at 1st jump then,sign conven is taking right as positive.


mu=-(M+m)v


so v=-mu/(M+m)


now the velocity of 2nd jump is u wrt this velocity so,its velo. wrt ground is


v'=-Mu/(m+M)


applying cons. of momentum on 2nd jump we get,


-mu=Mv"-mMu/(M+m)


from this we get v" as your ans

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details