Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        This question is about the forces needed to support  and to accelerate the train
a)the fully laden transrapid train has a mass of 200 tonnes.What is the force needed to lift it
b)the forward force on the transrapid train is produced by two forces FA and FB.
How the resultant will be horizontal
c)The angle theta is 30 degree and the magnitude of the force FA is 170000N.Calculate the total horizontal Force that FA and FB produce on the train
d)Calculate the acceleration of the train produced by 300000N and suggest a reason why its greater than the .67 ms-2 acceleration of the actual German Transrapid Maglev train whose mass is also 200 tonnes
```
7 years ago

105 Points
```										Dear rameeja,
The force required to lift the train is
F =  mg
F = 200*1000*9.81 = 1962000 N
consider  angle theta = angle a
Fa+Fb cos(a) = F net
Fb sin(a) = mg = 1962000
Fb*  (1/2) = 1962000
Fb = 1962000*2 = 3924000
Fb = 3924000
Fa+Fb cos(a) = F net
F  net = 170000 + 3924000*(cos(30)) = 3568283.6844
and  acceleration = F/m = 11.89

All the best.
Win exciting  gifts by answering the questions on Discussion  Forum. So help discuss any   query on askiitians forum and become an  Elite Expert League askiitian.

Suryakanth –IITB

```
7 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 551 off
USE CODE: CHEM20
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 594 off
USE CODE: CHEM20