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kanika kaul Grade: 12
        

                                                                      2 (square)


Q- integration (from sin x to 1) t  f(t) dt  = 1-sinx, for all x belongs to [ 0, pi/2) then f ( 1/root 3) is.

6 years ago

Answers : (4)

Anil Pannikar AskiitiansExpert-IITB
85 Points
										

Dear Kanika,


 


 differentiate both sides -


-sinx*f(sinx)* cosx = -cosx


or,  f(sinx) = 1/sinx


put sinx = X


then,  f(X) = 1/X


so, f(1/sqrt.3) = sqrt.3


 


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Askiitians Expert


Anil Pannikar


IIT Bombay

6 years ago
vikas askiitian expert
510 Points
										

differentiating  both sides wrt x


 we get


            -cosxsinxf(sinx)=-cosx


                      f(sinx)=1/sinx


                     f(t)=1/t


                      f(1/root3)=root3               ans


 

6 years ago
Devasish Bindani
45 Points
										

the ans i got is root3*(1-sinx) if it is not correct then please send me the answer and correct explanation for it

6 years ago
Vivek Nigam
28 Points
										

i think you shud revise bansal notes properly....you can easliy get the solution

6 years ago
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