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when t = 0, a particle at (1,0,0) moves towards (4,4,12) with a constant velocity of magnitude of  65 m/s. the position of the particle is measured in meters and time in sec. Assuming constant velocity the position of the particle at t= 2 sec is –

        (a)    (13i – 120j  +40k) m

        (b)    (40i  +31j – 120k) m

        (c)    (13i  – 40j + 12k) m

        (d)    (31i  + 40j + 120k) m

6 years ago


Answers : (1)


Dear sahil,

The correct answer is c)

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Sagar Singh

B.Tech, IIT Delhi

6 years ago

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