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`        two side of a triangle are √3 - 1 and √3 + 1 units and their included angle is 60° . solve the triangle . ?`
6 years ago

419 Points
```										Dear Arunav
Cos60=(√3 +1)2 + (√3 -1)2 -a2/2(√3 +1)(√3 -1)
solving a=√6
now use Cos formula to find out other angles like this

All the best.
AKASH GOYAL

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```
6 years ago
510 Points
```										let a,b are 31/2-1 , 31/3+1 & C = 60o        then
cosC = a2+b2-c2/2ab
ab = a2+b2-c2
3-1 + 6+2 -c2
c2 = 6
c = 61/2..................................1
now using a/sinA = b/sinB = c/sinC =k
sinA = asinC/c = (31/2-1/2*21/2)
A = 15o                ..............................2
A+B+C = 180
B + 60+15 = 180
B = 105o..........................3
```
6 years ago
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