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zahid sharief Grade: 11
        

two masses M1=1 kg and M2=2 kg are connected by a mass less spring. a force of 4N acts on the 2kg mass. what will be accn of M2 if accn of M1 is 1m/s^2

7 years ago

Answers : (2)

Anil Pannikar AskiitiansExpert-IITB
85 Points
										

Dear Zahid,


 FOr M1 : eq of motion -       M1 a1 = kx or kx = 1 N


For M2 : eq of motion  -     F - kx = M2a2     


                                        or  4 - 1 = 2 a2


                                              a2 = 3/2 m/s2


 


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Anil pannikar


IIT Bombay


 


 

7 years ago
suryakanth AskiitiansExpert-IITB
105 Points
										

Dear Zahid,


considering the free body diagram of M2,forces in it are,


F-Fspring = M2*a


on mass M1 ,forces in horizintal direction are


Fspring = M1*a1


Given s1 = 1 m/s^2


Hence Fspring = 1 N


M2*s2 = Fgiven - F spring


M2*s2 = 4 - 1 = 3 N


Hence accelaration of the MASS M2 = 1.5 m/s^2


Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.


All the best.


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Suryakanth –IITB

7 years ago
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