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```				   two masses M1=1 kg and M2=2 kg are connected by a mass less spring. a force of 4N acts on the 2kg mass. what will be accn of M2 if accn of M1 is 1m/s^2
```

6 years ago

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```										Dear Zahid,
FOr M1 : eq of motion -       M1 a1 = kx or kx = 1 N
For M2 : eq of motion  -     F - kx = M2a2
or  4 - 1 = 2 a2
a2 = 3/2 m/s2

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Anil pannikar
IIT Bombay

```
6 years ago
```										Dear Zahid,
considering the free body diagram of M2,forces in it are,
F-Fspring = M2*a
on mass M1 ,forces in horizintal direction are
Fspring = M1*a1
Given s1 = 1 m/s^2
Hence Fspring = 1 N
M2*s2 = Fgiven - F spring
M2*s2 = 4 - 1 = 3 N
Hence accelaration of the MASS M2 = 1.5 m/s^2
All the best.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Suryakanth –IITB
```
6 years ago

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