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Karthik Eyan Grade: 11
        

A variable line makes intercepts on the coordinate axes the sum of whose squares is constant and is equal to a^2. Find the locus of the foot of perpendicular from the origin to this line.

7 years ago

Answers : (1)

Anil Pannikar AskiitiansExpert-IITB
85 Points
										

Dear Karthik,


 


eq of line is x/p + y/q = 1 where p , q are intercept on x. y axis


alos given,  p2 + q2 = a2      eq 1


let foot of perpendicular is x1, y1


 


this point should lie on x/p + y/q = 1


so,  x1/p + y1 /q =1


 


also  (y1/x1 ) * ( - q/p ) = -1       eq2


find value of p, q from eq1 and eq2 and sunstitute in x1/p + y1 /q =1.


 

 


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Askiitians Expert


Anil Pannikar


IIT Bombay

7 years ago
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