Click to Chat
1800-2000-838
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Basic Concepts of Ellipse When an egg is sliced obliquely, a typical curve appears by its edge. The movement of earth around sun also traces a similar but a larger curve. This special curve is called ellipse. Now we proceed towards the mathematical definition of ellipse: An ellipse is locus of a point, which moves in a plane such that the ratio of its distances from a fixed point and a fixed line is constant and always less than one. In other words "Ellipse" is a conic for which the eccentricity e < 1. Let S be the focus of ellipse, P any point on the ellipse and PM perpendicular distance of the directrix from P, then SP/PM = e < 1 Major and Minor Axes By major axis, we mean the longest diameter. The axis which goes form one side of an ellipse to another passing through the center but along the widest part of the ellipse is called the major axis. Similarly, the minor axis is the shortest diameter that lies along the narrowest part of the ellipse. Semi-major and Semi-minor Axes The Semi-major Axis is half of the Major Axis, and the Semi-minor Axis is half of the Minor Axis. Let S be the focus and ZM be the directrix of the ellipse. Let e be its eccentricity. We draw SZ perpendicular to the directrix and divide SZ internally and externally in the ratio e: 1 and let A and A' be the internal and external point of division. Then we have SA = e AZ ...... (1) And SA' = e A'Z ...... (2) .·. A and A' lie on the ellipse. Let AA' = 2a and take O the midpoint of AA' as origin. Let P(x, y) be any point on the ellipse referred to OA and OB as co-ordinate axis. Then from figure it is evident that AS = AO - OS = a - OS AZ = OZ - OA = OZ - a A'S = A'O + OS = a + OS A'Z = OZ + OA' = OZ + a Substituting these values in (1) and (2), we have a - OS = e (OZ - a) ...... (3) a + OS = e (OZ + a) ...... (4) Adding (3) and (4), we get 2a = 2 e OZ Or OZ = a/e ...... (5) Subtracting (3) from (4), we get 2 OS = 2ae => OS = ae ...... (6) .·. The directrix MZ is x = OZ = a/e and the co-ordinate of the focus S are (OS, 0) i.e. (ae, 0). Now as P(x, y) lies on the ellipse. So we get SP = e PM or SP^{2} = e^{2} PM^{2} (x - ae)^{2} + y^{2} = e^{2} [OZ - x co-ordinate of P]^{2} => (x - ae)^{2} + y^{2} = e^{2} [a/e - x]^{2} = (a - ex)^{2} ...... (7) => x^{2} + a^{2}e^{2} - 2axe + y^{2} = a^{2} + e^{2}x^{2} - 2aex or x^{2}/a^{2} + y^{2}/a^{2}(1-e^{2}) = 1 [Dividing each term by a^{2} (1 - e^{2})] or x^{2}/a^{2} + y^{2}/b^{2} = 1 where b^{2} = a^{2} (1 - e^{2}) This is the standard equation of an ellipse, O is called the center of the ellipse, AA' and BB' are called the major and minor axes of ellipse (where b < a). There exists a second focus and second directrix for the curve. On the negative side of the origin take a point S', which is such that SO = S'O = ae and another point Z' such that ZO = OZ' = a/e. Draw Z'K' perpendicular to ZZ' and PM' perpendicular to Z'K' The equation (7) may also be written in the form (x + ae)^{2} + y^{2} = (a + ex)^{2} => S'P^{2} = e^{2} (PM')^{2} Hence, any point P on the curve is such that its distance from S' is e times to its distance from Z'K' so we should have obtained the same curve, if we had started with S' as focus, a Z'K' as directrix and the same eccentricity. Pause: We have considered a > b, now if we consider b > a, what will be the shape of the ellipse x^{2}/a^{2} +y^{2}/b^{2}? In this case the major axis AA' of the ellipse is along the y-axis and is of length 2b. See figure. The minor axis of BB' = 2a. The foci S and S' are (0, be) and (0, -be) respectively. The directrix are MZ and M'Z' given by y = + b/e, respectively. Also here a^{2} = b^{2} (1 - e^{2}). Note: Let P(x_{1}, y_{1}) be any point. This point lies outside, on or inside the ellipse (8) according as x^{2}_{1}/a^{2} + y^{2}_{1}/b^{2} = 1 > 0 or = 0 or < 0. Central Curve A curve is said to be a central curve if there is a point, called the centre, such that every chord passing through it is bisected at it. Latus rectum: The length of a chord through the focus and at right angle to the major axis of the ellipse is known as the latus rectum of the ellipse. There being two foci of an ellipse, there are two rectum, which are of equal length. yL = b^{2}/a .·. The length of latus rectum LSL' = 2b^{2}/a Notes:
When an egg is sliced obliquely, a typical curve appears by its edge. The movement of earth around sun also traces a similar but a larger curve. This special curve is called ellipse. Now we proceed towards the mathematical definition of ellipse:
An ellipse is locus of a point, which moves in a plane such that the ratio of its distances from a fixed point and a fixed line is constant and always less than one.
In other words "Ellipse" is a conic for which the eccentricity e < 1. Let S be the focus of ellipse, P any point on the ellipse and PM perpendicular distance of the directrix from P, then
SP/PM = e < 1
Major and Minor Axes
By major axis, we mean the longest diameter. The axis which goes form one side of an ellipse to another passing through the center but along the widest part of the ellipse is called the major axis. Similarly, the minor axis is the shortest diameter that lies along the narrowest part of the ellipse.
Semi-major and Semi-minor Axes
The Semi-major Axis is half of the Major Axis, and the Semi-minor Axis is half of the Minor Axis.
Let S be the focus and ZM be the directrix of the ellipse. Let e be its eccentricity.
We draw SZ perpendicular to the directrix and divide SZ internally and externally in the ratio e: 1 and let A and A' be the internal and external point of division.
Then we have SA = e AZ ...... (1)
And SA' = e A'Z ...... (2)
.·. A and A' lie on the ellipse.
Let AA' = 2a and take O the midpoint of AA' as origin. Let P(x, y) be any point on the ellipse referred to OA and OB as co-ordinate axis.
Then from figure it is evident that
AS = AO - OS = a - OS
AZ = OZ - OA = OZ - a
A'S = A'O + OS = a + OS
A'Z = OZ + OA' = OZ + a
Substituting these values in (1) and (2), we have
a - OS = e (OZ - a) ...... (3)
a + OS = e (OZ + a) ...... (4)
Adding (3) and (4), we get
2a = 2 e OZ
Or OZ = a/e ...... (5)
Subtracting (3) from (4), we get
2 OS = 2ae => OS = ae ...... (6)
.·. The directrix MZ is x = OZ = a/e and the co-ordinate of the focus S are (OS, 0) i.e. (ae, 0). Now as P(x, y) lies on the ellipse.
So we get
SP = e PM or SP^{2} = e^{2} PM^{2}
(x - ae)^{2} + y^{2} = e^{2} [OZ - x co-ordinate of P]^{2}
=> (x - ae)^{2} + y^{2} = e^{2} [a/e - x]^{2} = (a - ex)^{2} ...... (7)
=> x^{2} + a^{2}e^{2} - 2axe + y^{2} = a^{2} + e^{2}x^{2} - 2aex
or x^{2}/a^{2} + y^{2}/a^{2}(1-e^{2}) = 1 [Dividing each term by a^{2} (1 - e^{2})]
or x^{2}/a^{2} + y^{2}/b^{2} = 1 where b^{2} = a^{2} (1 - e^{2})
This is the standard equation of an ellipse, O is called the center of the ellipse, AA' and BB' are called the major and minor axes of ellipse (where b < a).
There exists a second focus and second directrix for the curve. On the negative side of the origin take a point S', which is such that SO = S'O = ae and another point Z' such that ZO = OZ' = a/e.
Draw Z'K' perpendicular to ZZ' and PM' perpendicular to Z'K'
The equation (7) may also be written in the form
(x + ae)^{2} + y^{2} = (a + ex)^{2}
=> S'P^{2} = e^{2} (PM')^{2}
Hence, any point P on the curve is such that its distance from S' is e times to its distance from Z'K' so we should have obtained the same curve, if we had started with S' as focus, a Z'K' as directrix and the same eccentricity.
Pause:
We have considered a > b, now if we consider b > a, what will be the shape of the ellipse x^{2}/a^{2} +y^{2}/b^{2}? In this case the major axis AA' of the ellipse is along the y-axis and is of length 2b. See figure.
The minor axis of BB' = 2a. The foci S and S' are (0, be) and (0, -be) respectively. The directrix are MZ and M'Z' given by y = + b/e, respectively. Also here a^{2} = b^{2} (1 - e^{2}).
Note:
Let P(x_{1}, y_{1}) be any point. This point lies outside, on or inside the ellipse (8) according as x^{2}_{1}/a^{2} + y^{2}_{1}/b^{2} = 1 > 0 or = 0 or < 0.
Central Curve
A curve is said to be a central curve if there is a point, called the centre, such that every chord passing through it is bisected at it.
Latus rectum:
The length of a chord through the focus and at right angle to the major axis of the ellipse is known as the latus rectum of the ellipse.
There being two foci of an ellipse, there are two rectum, which are of equal length.
yL = b^{2}/a
.·. The length of latus rectum LSL' = 2b^{2}/a
Notes:
Focal Distance of a Point
Since S'P = ePN', SP = ePN,
S'P + SP = e (PN + PN')
= e (NN') = e (2a/e) = 2a
=> The sum of the focal distances of any point on the ellipse is equal to its major axis.
You can get an idea about the type of questions asked by seeing the past year papers.
Another definition of an ellipse
Let ellipse be x^{2}/a^{2} +y^{2}/b^{2} = 1 ...... (i)
Its foci S and S' are (ae, 0) and (-ae, 0). The equation of its directrices MZ and M'Z' are x = a/e and x = -a/e respectively. Let P(x_{1}, y_{1}) be any point on (i)
Now SP = e PM = e NZ = e (OZ - ON) = e[(a/e)-x_{1}] = a - ex_{1}
and S'P = ePM' = e (Z'N) = e (OZ' + ON) = e[(a/e) + x_{1}] = a + ex_{1}
.·. SP + S'P = 2a = AA'
So by this property an ellipse can also be defined as "the locus of a point which moves such that the sum of its distances from two fixed point is always constant.
Other Forms
Let the eccentricity of the ellipse be e (e < 1).
If P(x, y) is any point on the ellipse, then
PS^{2} = e^{2} PM^{2}
=> (x - h)^{2} + (y - k)^{2} = e^{2}(ax+by+c)^{2}/(a^{2} + b^{2} ), , which is of the form
ax^{2} + 2hxy + by^{2} + 2gx + 2fy + c = 0 ... (*) where
Δ = abc + 2fgh + af^{2} - bg^{2} - ch^{2} ≠ 0, h^{2} < ab.
These are the necessary and sufficient conditions for a general quadratic equation given by (*) to represent an ellipse.
For more, look into the video
Position of a Point Relative to an Ellipse
The point P(x_{1}, y_{1}) is outside or inside the ellipse x^{2}/a^{2} + y^{2}/b^{2} = 1, according as the quantity ((x_{1}^{2})/a^{2} +(y_{1}^{2})/b^{2} -1) is positive or negative.
Parametric Equation of an Ellipse
Clearly, x = a cosθ, y = b sinθ satisfy the equation x^{2}/a^{2} +y^{2}/b^{2} = 1 for all real values of θ.
Hence, the parametric equations of the ellipse x^{2}/a^{2} +y^{2}/b^{2} = 1 are x = a cosθ, y = b sinq where θ is the parameter.
Also (a cos θ, b sin θ) is a point on the ellipse x^{2}/a^{2} +y^{2}/b^{2} = 1 for all values of θ(0 < θ < 2Π).
The point (a cosθ, b sinθ) is also called the point θ. The angle θ is called the eccentric angle of the point (a cosθ, b sinθ) on the ellipse.
Draw a circle with AA' (the major axis) as the diameter. This circle is called the auxiliary circle of the ellipse. The equation of the circle is x^{2} + y^{2} = a^{2}. Any point Q on the circle is (a cosθ, a sinθ). Draw QM as perpendicular to AA' cutting the ellipseat P. The x-co-ordinate of P = CM = a cosθ.
=> y-co-ordinate of P is b sinθ
=> P ≡ (a cosθ, b sinθ).
Area of an ellipse
Suppose j is the major axis of the ellipse and n is the minor axis. Then the area of the ellipse is given by the formula
Area=π jn
Illustration:
Find the equation of an ellipse centered at the origin with major axis of length 10 lying along the x-axis and minor axis of length 6 along the y-axis. Solution:
The major axis has length 10 along the x-axis and is centered at (0, 0), so its
endpoints are at (-5,0) and (5,0).
Hence, we get a = 5 and b = 3. So the required equation of the ellipse is
x^{2}/5^{2} + y^{2}/ 3^{2} = 1 or x^{2} / 3^{2} + y^{2}/ 5^{2 }= 1.
Find the equation of the ellipse, which cuts the intercept of length 3 and 2 on positive x and y-axis. Centre of the ellipse is origin and major and minor axes are along the positive x-axis and along positive y-axis.
Solution:
x^{2}/a^{2} +y^{2}/b^{2} = 1 ...... (1)
According to the given condition the ellipse (1) passes through (3, 0) and (0, 2), so we have.
9/a^{2} = 1 => a^{2} = 9
And 4/b^{2} = 1 => b^{2} = 4
Therefore, the equation of the ellipse is x^{2}/9 + y^{2}/4 = 1
Obtain the equation of an ellipse whose focus is the point (-1, 1) whose directrix is the line passing through (2, 5) having the unit gradient and whose eccentricity is ½.
Let P(x, y) be any point on ellipse.
Its focus is S (-1, 1).
Let the directrix be y = x + c ...... (1)
(·.· gradient m = 1)
Line (1) passes through (2, 5) so,
5 = 2 + c => c = 3
The directrix is y = x + 3
=> x - y + 3 = 0 ...... (2)
Now let PM be the perpendicular from P, drawn to its directrix
(2). By definition of ellipse SP = e PM
or SP^{2} = e^{2} PM^{2}
=> (x + 1)^{2} + (y - 1)^{2} = (1/2)^{2} [(x-y+3)/√((1^{2}+1^{2} ))]^{2}
=> 8[(x + 1)^{2} + (y - 1)^{2}] = (x - y + 3)^{2}
=> 7x^{2} + 7y^{2} + 2xy + 10x - 10y + 7 = 0,
This is the required equation of ellipse.
To read more, Buy study materials of Ellipse comprising study notes, revision notes, video lectures, previous year solved questions etc. Also browse for more study materials on Mathematics here.
Signing up with Facebook allows you to connect with friends and classmates already using askIItians. It’s an easier way as well. “Relax, we won’t flood your facebook news feed!”
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
Tangent and Normal The line y = mx + c meets the...
Solved Examples of Ellipse: Example 1: Find the...
Propositions on Ellipse The standard equation of...