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a hemisphere (μ=3) of radius placed on a horizontal surface with its base touching the surface .A vertical beam of cross sectional radius (√3/2)r is incident symmetrically on its curved surface.find radius of the spot of light formed on the horizontal surface??????
Dear Abhishiek,
We know that For hemissherical surface
f = R/(n-1) and refractive n= 3 here
and Magnification is given by M= -S2/S1= f/ f-S1 and S2 is on the other side i.e., on the ground we would get +ve otherwise it would have been -ve
By substituting S1= (√3/2)R
We get S2= S1/(√3-1) Where S1= (√3/2)R
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