Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        Two wires of different densities but same area of cross section are soldered together at one end and are stretched to a tension T. The velocity of a transverse wave in the first wire is double of that in the second wire. Find the ratio of the density of the first wire to that of second wire. `
3 years ago

Deepak Patra
474 Points
```										Sol. Let v1 = velocity in the 1st string
⇒ v1 = √(T /m1)
Because m1 = mass per unit length = (1a1l1 / l1) = 1a1 where a1 = Area of cross section
⇒ v1 = √(T / p1a1) …(1)
Let v2 = velocity in the second string
⇒ v2 = √(T /m2 )
⇒ v2 = √(T / p2a2 ) …(2)
Given that, v1 = 2v2
⇒ √(T / p1a1) = 2 √(T / p2a2 ) ⇒ (T/a1p1) = 4(T/a2p2)
⇒ p1/p2 = 1/4 ⇒ p1 : p2 = 1 : 4 (because a1 = a2)

```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Wave Motion

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 413 off
USE CODE: COUPON10
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 445 off
USE CODE: COUPON10