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Amit Saxena Grade: upto college level
`        Two successive resonance frequencies in an open organ pipe are 1944 Hz and 2592 Hz. Find the length of the tube. The speed of sound in air is 324 m s-1.`
3 years ago

Navjyot Kalra
654 Points
```										Sol. Let the length of the longer tube be L base 2 and smaller will be L base 1.
According to the data 440 = 3 * 330/4 * L base 2 …..(1) (first over tone)
and 440 = 330/4 * L base 1 ….(2) (fundamental)
solving equation we get L base 2 = 56.3 cm and L base 1= 18.8 cm.

```
3 years ago
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