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Shane Macguire Grade: upto college level
         A closed organ pipe can vibrate at a minimum frequency of 500 Hz. Find the length of the tube. Speed of sound in air = 340 m s-1.
3 years ago

Answers : (1)

Deepak Patra
askIITians Faculty
474 Points
										Sol. V = 340 m/s

Distances between two nodes or antinodes
⇒ λ/4 = 25 cm
⇒ λ = 100 cm = 1 m
⇒ n = v/λ = 340 Hz.
3 years ago
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