A closed organ pipe can vibrate at a minimum frequency of 500 Hz. Find the length of the tube. Speed of sound in air = 340 m s-1.

Question

Deepak Patra · Answer

Sol. V = 340 m/s Distances between two nodes or antinodes ⇒ λ/4 = 25 cm ⇒ λ = 100 cm = 1 m ⇒ n = v/λ = 340 Hz.

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A closed organ pipe can vibrate at a minimum frequency of 500 Hz. Find the length of the tube. Speed of sound in air = 340 m s-1.

A closed organ pipe can vibrate at a minimum frequency of 500 Hz. Find the length of the tube. Speed of sound in air = 340 m s-1.

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A closed organ pipe can vibrate at a minimum frequency of 500 Hz. Find the length of the tube. Speed of sound in air = 340 m s-1.

A closed organ pipe can vibrate at a minimum frequency of 500 Hz. Find the length of the tube. Speed of sound in air = 340 m s-1.

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