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```				   Q:- A string of length 'l' is fixed at both ends.It is vibrating in its 3rd overtone with maximum amplitude 'a'.The amplitude at a distance l/3 from one end is:
A. a
B. 0
C. (√3/2)a
D.a/2
```

7 years ago

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```										Dear Tapasranjan

It is vibrating in its 3rd overtone then you will get nodes at x=0 ,l/4,2l/4,3l/4,l

equation of motion is

y= a sin(4?x/l)coswt
put x=l/3
amplitude =a sin(4?l/3l)
=a sin(4?/3)
=a(v3/2)

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If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.

All the best.

Regards,

```
7 years ago

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