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        Two vectors ,  (vector A) and (vector B) have equal magnitudes. If magnitude of  (vector A + vector B) is equal to n times the magnitude of (vector A – vector B), then the angle between (vector A) and (vector B) is: Answer :  cos^-1(n^2 – 1/n^2 + 1)or negative cosine of n(square)  minus 1 over n(square)  plus 1. could some one explain the solution.  this question is from odisha JEE 2010.
2 years ago

Piyush
112 Points
										From here you will get

2 years ago
RIYAZSHAIK
59 Points
										 										its ok are not .please feedback me.From here you will get										if u satisfied with my answer you can approve me

one year ago
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