MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Pushkar soni Grade: 11
        
Two vectors ,  (vector A) and (vector B) have equal magnitudes. If magnitude of  (vector A + vector B) is equal to n times the magnitude of (vector A – vector B), then the angle between (vector A) and (vector B) is:
 
Answer :  cos^-1(n^2 – 1/n^2 + 1)
or negative cosine of n(square)  minus 1 over n(square)  plus 1.
 
could some one explain the solution.  this question is from odisha JEE 2010.
 
2 years ago

Answers : (2)

Piyush
askIITians Faculty
112 Points
										\left |A+B \right |^{2}=n^{2}\left | A-B \right |^{2}
A^{2}+B^{2}+2ABcos\theta =n^{2}\left \{ A^{2}+B^{2}-2ABcos\theta \right \}
From here you will get
cos\theta =\frac{n^{^{2}}-1}{n^{2}+1}
2 years ago
RIYAZSHAIK
59 Points
										
 
its ok are not .please feedback me.cos\theta =\frac{n^{^{2}}-1}{n^{2}+1}From here you will getA^{2}+B^{2}+2ABcos\theta =n^{2}\left \{ A^{2}+B^{2}-2ABcos\theta \right \}\left |A+B \right |^{2}=n^{2}\left | A-B \right |^{2}
if u satisfied with my answer you can approve me
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
Get extra Rs. 15,900 off
USE CODE: AR07
  • Statistics and Probability
  • OFFERED PRICE: Rs. 636
  • View Details
Get extra Rs. 636 off
USE CODE: AR07

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details