MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Tapasranjan Das Grade: 12
        

The equation of a plane through the line of intersection of 2x+3y+z-1=0 and x+5y-2z+7=0 and parallel to the line y=0=z is _______________

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Tapasranjan Das


equation of a plane through the line of intersection of 2x+3y+z-1=0 and x+5y-2z+7=0  is


2x+3y+z-1+ λ(x+5y-2z+7)=0


(2+λ)x +(3+5λ)y +(1-2λ)z -1-7λ=0


it is parallel to x axix so


(2+λ).1 +(3+5λ).0 +(1-2λ).0 =0


 2+λ=0


λ=-2


so equation of plane is   -7y +5z +13=0




Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.


 All the best.
 
Regards,
Askiitians Experts
Badiuddin


 


 


 

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
  • Statistics and Probability
  • OFFERED PRICE: Rs. 636
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details