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`        ABCD is a parallelogarm. M is the mid point of side BC. a line is draw  AM which cut the BD at O. find the  area of quadilateral OMCD`
6 years ago

36 Points
```										Dear student,
triangle AOD and OMB are similar since all angles are same
=> BO = 1/3*BD and we know vector BD is sum of vectors of BA,AD
so area of triangle OBM = (1/2)*|BO X BM|
BM = BC/2
Area of quad OMCD = area of triangle BCD - area of triangle OBM
area of triangle BCD = (1/2)|AB X AD|
=> Area of quad OMCD = (1/2)|AB X AD| - (1/2)*(1/6)|(BA+AD) X BC|=> Area of quad OMCD = (1/2)|AB X BC| - (1/2)*(1/6)|(BC-AB) X BC|
```
6 years ago
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