0

Guest

Courses New

PROVE THAT (1+tanAtanB) 2 +(tanA-tanB) 2 =sec 2 A×sec 2 B

  PROVE THAT                                                      (1+tanAtanB)2+(tanA-tanB)2=sec2A×sec2B

Grade:10

1 Answers

Aakanksha Talreja
34 Points
8 years ago
Expand it n factorise it u will get d result
1+\tan ^{2}A*\tan ^{2}B+2\tan A\tan B+\tan ^{2}A+\tan ^{2}B-2\tan A\tan B=1+\tan ^{2}A+\tan ^{2}A*\tan ^{2}B+\tan ^{2}B=(1+\tan ^{2}A)(1+\tan ^{2}B)=\sec ^{2}A\sec ^{2}B

Think You Can Provide A Better Answer ?

Other Related Questions on Trigonometry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More