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)In a triangle ABC, a=5,b=4 & cos(A-B)=31/32, then side c=.....?

)In a triangle ABC, a=5,b=4 & cos(A-B)=31/32, then side c=.....?

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1 Answers

Ravi
askIITians Faculty 69 Points
9 years ago
Convert cos(A-B) in terms of tan(A-B)/2. Use tan rule or Napier analogy over a,b to find the value of angle C. Use cosine law(Cos C) to find the value of c.
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