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sin-1x + sin-12x = ∏/3
Dear Aby
-1≤ 2x≤1
-1/2 ≤x≤1/2
now
sin-12x = ∏/3 -sin-1x take sin
sin-12x = ∏/3 -sin-1x
take sin
2x = sin∏/3 cos sin-1x -cos∏/3 sinsin-1x
=√3 /2 √(1-x2) -1/2 x
or 5x/2 =√3 /2 √(1-x2)
square
25x2 =3 (1-x2)
x2 =3/28
x= =±√3/28
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