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```        IN A TRIANGLE ABC , tan A/2=5/6
and tan c/2=2/5 then
a)a.b.c are in A P
b)cos A,cos b, cos C are in AP
c)sin a,sin b,sin c are in GP
d)none of these```
6 years ago

510 Points
```										tanA/2 = [(s-b)(s-c)/s(s-a)]1/2                 ....................1
tanC/2 = [(s-a)(s-b)/s(s-c)]1/2                ..................2

eq1 * eq2 = tanA/2tanB/2 = [s-b/s]              .................3

tanA/2 = 5/6          (given)
tanC/2 = 2/5          (given)

tanA/2tanB/2 = 5/6*2/5 = 1/3
from eq 3 , (s-b)/s = 1/3
3s - 3b = s
2s = 3b
2(a+b+c)/2 = 3b
a+c = 2b
a,b,c are in AP
approve if u like my ans
```
6 years ago
510 Points
```										dear GAVEESH
a,b,c are in AP .........
```
6 years ago
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