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GAVEESH bhardwaj Grade: 11
        IN A TRIANGLE ABC , tan A/2=5/6

and tan c/2=2/5 then
a)a.b.c are in A P
b)cos A,cos b, cos C are in AP
c)sin a,sin b,sin c are in GP
d)none of these
6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										

tanA/2 = [(s-b)(s-c)/s(s-a)]1/2                 ....................1


tanC/2 = [(s-a)(s-b)/s(s-c)]1/2                ..................2


 


eq1 * eq2 = tanA/2tanB/2 = [s-b/s]              .................3


 


tanA/2 = 5/6          (given)


tanC/2 = 2/5          (given)


 


tanA/2tanB/2 = 5/6*2/5 = 1/3


from eq 3 , (s-b)/s = 1/3


    3s - 3b = s


    2s = 3b


   2(a+b+c)/2 = 3b


    a+c = 2b


a,b,c are in AP


approve if u like my ans

6 years ago
vikas askiitian expert
510 Points
										

dear GAVEESH


a,b,c are in AP .........

6 years ago
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