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rahul verma Grade: 12
        

  • the domain of defination of f(x) =log2(x+3)/x2+3x+2


 

7 years ago

Answers : (1)

Khushboo Singh
16 Points
										

f(x)=log2(x+3)/(x2+3x+2)  =log2(x+3)/(x+1)(x+2)


x+3>0  =>x>-3   -----(1)


(x+1)(x+2) ≠ 0


x ≠-1,-2  ----(2)


from eq (1) and (2)


domain is (-3,∞)/{-1.-2}

7 years ago
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