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somesh kumar Grade:
        

solve the equation


 


cos3X sin3(cube)X + sin3X cos3(cube)X  =  0

6 years ago

Answers : (1)

suryakanth AskiitiansExpert-IITB
105 Points
										

Dear somesh,


we know that,


cos^3x=(cos3x+3cosx)/4 and  sin^3x=(3sinx-sin3x)/4                    [since cos3x=4cos^x-3cosx]


substuting in the given equation


cos3X sin3(cube)X + sin3X cos3(cube)X  =  0


cos3x{(3sinx-sin3x)/4}+sin3x{(cos3x+3cosx)/4} = 0


{3sinxcos3x-cos3xsin3x+sin3xcos3x+3cosxsin3x}/4 = 0


3/4(sinxcos3x+cosxsin3x) = 0


sin4x = 0


Hence x=n∏/4


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6 years ago
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