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Prove that sin2n+  cos2nx ≤ 1 for all x and n≥1

6 years ago


Answers : (1)


Dear Manoj,


0<=sin^2(x) ,cos^2(x)<=1 for all x

therefore , sin^2n(x) <=sin^2x and cos^2n(x)<=cos^2(x) for n>=1


adding both we get  sin2nx +  cos2nx ≤ 1



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6 years ago

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