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Manoj Jangra Grade: 12
        

Find  the set of possible values of tan(x+pi/6)tanx  wher x is any real angle

6 years ago

Answers : (1)

Chetan Mandayam Nayakar
312 Points
										

let tan(x+pi/6)tanx=k, implies tanx(tanx+(1/√3))/(1-(tanx/√3))=k,implies tan2x +tanx((k+1/√3))-k=0, this quadratic equation in tanx has a non-negative discriminant. thus,(k+1)2/3≥ -4k, k2 +14k +1≥0,the "roots" of this quadratic inequality are -7-4√3 and -7+4√3. therefore, the set of possible values is (-∞,-7-4√3] U [-7+4√3,∞)


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