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Samyuktha Shankar Grade:
        

sin(37) ???

7 years ago

Answers : (9)

Sona Srivastava
38 Points
										

in a right angled triangle with sides as 3,4,5 or 6,8,10 the angles other than the right angle are 37° and 53° 
so


sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°

7 years ago
fgdgd
13 Points
										
fgfdg\sum \prod \Cap \setminus \lozenge \blacklozenge \blacksquare \triangle \triangleleft \gamma \varpi \mu \nu \iota \kappa \eta \zeta \omega \phi \sigma
7 months ago
utpal raj
244 Points
										
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
this is very important for exam point of view so remember this …
good luck
 
7 months ago
llol
11 Points
										
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
is correct so do some revision on this\!!!!!!!!!!!!!!!!!!!!!
5 months ago
Prince Zrk
26 Points
										Remember cos as father Cos 53 =5/3 just oppositeAnd sin is reverse so 5/3=sin 37And one value is 4/5 So cos37and sin53 is for thatThanks
										
4 months ago
Aman sharma
11 Points
										Exact value of sin37° & cos37° areSin37°=0.601Cos37°=0.798°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
										
4 months ago
Karthi
13 Points
										Its very simple construct a triangle sides 3,4,5 and mark the angle thita  now one angle will be 90`,53` and 37` now by using sin and cos thita ratios we can find the angles that isSin37`= opposite / hypotaneus = 3/5Similarly :Sin53`= 4/5Cos37` = 3/5cos53`= 3/5
										
one month ago
HJHJHJHJH
14 Points
										
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
it is so simle
 
10 days ago
HJHJHJHJH
14 Points
										
 
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
it is so simple 
srry for the mistake
 
10 days ago
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