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Samyuktha Shankar Grade:
        

sin(37) ???

6 years ago

Answers : (6)

Sona Srivastava
38 Points
										

in a right angled triangle with sides as 3,4,5 or 6,8,10 the angles other than the right angle are 37° and 53° 
so


sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°

6 years ago
fgdgd
13 Points
										
fgfdg\sum \prod \Cap \setminus \lozenge \blacklozenge \blacksquare \triangle \triangleleft \gamma \varpi \mu \nu \iota \kappa \eta \zeta \omega \phi \sigma
3 months ago
utpal raj
231 Points
										
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
this is very important for exam point of view so remember this …
good luck
 
3 months ago
llol
11 Points
										
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
is correct so do some revision on this\!!!!!!!!!!!!!!!!!!!!!
29 days ago
Prince Zrk
26 Points
										Remember cos as father Cos 53 =5/3 just oppositeAnd sin is reverse so 5/3=sin 37And one value is 4/5 So cos37and sin53 is for thatThanks
										
15 days ago
Aman sharma
11 Points
										Exact value of sin37° & cos37° areSin37°=0.601Cos37°=0.798°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
										
8 days ago
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